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Crazy boy [7]
3 years ago
15

The bar graph below shows the student's favorite ice cream flavors. a) Use the graph's lines as a ruler to draw the intervals on

the number line shown above. Then plot and label a point for each flavor on the number line. B) Write a number sentence to show the total number of students who voted for butter pecan, Vanilla, and chocolate.

Mathematics
1 answer:
PtichkaEL [24]3 years ago
3 0
Butter pecan: 25
Vanilla: 35
Chocolate: 50

The dotted line between 20 and 30 (butter pecan) will be nothing more than anything including 5. In this case, it is 25 counting up to 30.
The solid lines directly leading to a number will be that number, for instance, chocolate is 50.
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BaLLatris [955]

Answer:  c. 7,999,999 phone numbers

A can be any digit 2-9, then there are 8 possible numbers.

B can be any digit 0-9, then there are 10 possible numbers.

C can be any digit 0-9, then there are 10 possible numbers.

X can be any digit 0-9, then there are 10 possible numbers.

X can be any digit 0-9, then there are 10 possible numbers.

X can be any digit 0-9, then there are 10 possible numbers.

X can be any digit 0-9, then there are 10 possible numbers.

Then are possible: 8·10·10·10·10·10·10 = 8·10⁶ = 8,000,000 phone numbers

But the number 867-5309 is not used then 8,000,000 - 1 = 7,999,999 possible phone numbers.

Answer: c. 7,999,999 phone numbers

\textit{\textbf{Spymore}}  

6 0
3 years ago
Expand: x(3 + 9). please
Oksi-84 [34.3K]

Answer:

x(3 + 9) = 3x + 9x = 12x

Step-by-step explanation:

...........

8 0
3 years ago
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raketka [301]
I think I is the Answer

5 0
3 years ago
How many eight-digit serial numbers contain three of one digit, two of another digit, two of yet another digit, and one of still
Harlamova29_29 [7]

It is easier to understand the problem if you create a number based on the criteria and then perform the computations. I am going to choose: 111 22 33 4

There are 10 options for the first "1" and only 1 option for the other two 1's

There are 9 remaining options for the first "2" and only 1 option for the other 2

There are 8 remaining options for the first "3" and only 1 option for the other 3

There are 7 remaining options for the "4"

10 x 1 x 1    x      9 x 1     x      8 x 1      x      7

10 x 9 x 8 x 7 = 5,040

Answer: 5,040

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3 years ago
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Count 12 spaces down and 1 space to right i think
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3 years ago
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