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Harlamova29_29 [7]
3 years ago
13

Does (x+1) squared minus x squared equal 2x+1

Mathematics
1 answer:
Aleks [24]3 years ago
6 0

Answer:

Yes does

Step-by-step explanation:

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Which expression is equivalent to5(h+9)
Fantom [35]

Answer:

The answer would be 5h+45

Step-by-step explanation

5 (h+9)

You need to convert this equation into the equation

you multiply 5 by h and get 5h

Then multiply the same number outside the parenthesis, 5, by 9 which will give you the answer 45

Once you have 5h and 45 just put it together with the addition symbol which will will equal:

5 (h+9) = 5h + 45

Your Welcome! (hopefully this answers your question)

4 0
3 years ago
9*10^7 is how many times as large as 3*10^3 Please help
sesenic [268]

Answer:

30000 times larger.

Step-by-step explanation:

10^7 * 9/10^3*3

Law of exponents cancel some of the tens.

10^4 * 9/3

Cancel out the three.

10^4 *3

Compute

30000 times larger.

4 0
3 years ago
Cards are drawn, one at a time, from a standard deck; each card is replaced before the next one is drawn. Let X be the number of
steposvetlana [31]

Cards are drawn, one at a time, from a standard deck; each card is replaced before the next one is drawn. Let X be the number of draws necessary to get an ace. Find E(X) is given in the following way

Step-by-step explanation:

  • From a standard deck of cards, one card is drawn. What is the probability that the card is black and a jack? P(Black and Jack)  P(Black) = 26/52 or ½ , P(Jack) is 4/52 or 1/13 so P(Black and Jack) = ½ * 1/13 = 1/26
  • A standard deck of cards is shuffled and one card is drawn. Find the probability that the card is a queen or an ace.

P(Q or A) = P(Q) = 4/52 or 1/13 + P(A) = 4/52 or 1/13 = 1/13 + 1/13 = 2/13

  • WITHOUT REPLACEMENT: If you draw two cards from the deck without replacement, what is the  probability that they will both be aces?

P(AA) = (4/52)(3/51) = 1/221.

  • WITHOUT REPLACEMENT: What is the probability that the second card will be an ace if the first card is a  king?

P(A|K) = 4/51 since there are four aces in the deck but only 51 cards left after the king has been  removed.

  • WITH REPLACEMENT: Find the probability of drawing three queens in a row, with replacement. We pick  a card, write down what it is, then put it back in the deck and draw again. To find the P(QQQ), we find the

probability of drawing the first queen which is 4/52.

  • The probability of drawing the second queen is also  4/52 and the third is 4/52.
  • We multiply these three individual probabilities together to get P(QQQ) =
  • P(Q)P(Q)P(Q) = (4/52)(4/52)(4/52) = .00004 which is very small but not impossible.
  • Probability of getting a royal flush = P(10 and Jack and Queen and King and Ace of the same suit)
5 0
3 years ago
What is the slope of the line passing through the points (2, −5) and (4, 1)? 2 ​−4/5 ​ ​ 5/4 ​ 3
satela [25.4K]
Just use y2-y2/x2-x1

so

1+5 (because subtracting a negative is the same as adding a positive)

4-2


6/2

or 3/1 which is the same as 3
3 0
3 years ago
9. (12 pts) daniel is paying $600 for his auto insurance, and he is wondering if he is overpaying compared to his friends. he se
Karolina [17]

Answer:

Step-by-step explanation:

1) The sample and the population of this study is the friends who replied his email which includes in his contact list. then, the number of the replied to his email are 9 friends.

population: the whole friends include in his contact list.

3) Type I error occurs when one incorrectly rejects the null hypothesis

Here there is possibility of type I error

7 0
3 years ago
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