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Ad libitum [116K]
4 years ago
5

Find the greatest common factor of 63 and 96

Mathematics
2 answers:
allochka39001 [22]4 years ago
8 0
GCF of 63 and 96 = 3
julia-pushkina [17]4 years ago
4 0
The greatest common factor (GCF) of 63 and 96 is: 3

To find the GCF, list all the factors until that go up to 63 since that is the minimum.
Factors of 63: 1, 3, 7, 9, 21, 63
Factors of 96: 1, 2, 3, 4, 6, 8, 12, 16, 24, 32, 48

Find the common factors between the two numbers which are 1 and 3. Now, which one of those numbers are the greatest/highest? The answer is 3.
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6th grade math plz help me
vlabodo [156]

Answer:

The mode, which is 7, is not a typical distance for the data. The median, which is 3.5, is not a typical distance for the data. The mean, which is 4, is a typical distance for the data. So, Grace’s reasoning is not correct.

5 0
3 years ago
write an even number that has a 7 in the hundreds place , has an odd number in the thousands place and is multiple of 10
Serjik [45]
Even numbers end with 0,2,4,6,8

7 in hundreds place

odd in thousands place, odd numbers are 1,3,5,7,9

multiplue of 10 end with 0

so therfor the number has 7 in hundreds place and ends with 0 with odd in thousands and undefined hundreds place

50 options

some examples are
1730
9790

any number, x7y0 such that x is odd and y can be any number
7 0
3 years ago
Find the area of the isosceles triangle.
kogti [31]

Answer:

The hight length : h

The base length : a

Apply the Pythagorean theorem in the right triangle :

h² = 13² - (10/2) = 144

h  = √144 = 12 cm

S = (a x h)/ 2 = ( 10 x 12 )/2 = 60 cm²

Step-by-step explanation:

5 0
3 years ago
32. Find the ratio of the side lengths of the small triangle to the large
kupik [55]

Answer:

2/3

Step-by-step explanation:

that the ratio of that number

8 0
2 years ago
Can someone help! I know the answer I just need step by step!
baherus [9]

Answer:

4 \sqrt{2}

Step-by-step explanation:

Rewrite 32 as the product of 16 and 2:

\implies \sqrt{32}=\sqrt{16 \cdot 2

Apply exponent rule \sqrt{a \cdot b}=\sqrt{a}\sqrt{b}

\implies \sqrt{16 \cdot 2}=\sqrt{16}\sqrt{2}

Rewrite 16 as 4²:

\implies \sqrt{16}\sqrt{2}=\sqrt{4^2}\sqrt{2}

Apply exponent rule \sqrt{a^2}=a

\implies \sqrt{4^2}\sqrt{2}=4 \sqrt{2}

6 0
2 years ago
Read 2 more answers
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