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Ad libitum [116K]
3 years ago
5

Find the greatest common factor of 63 and 96

Mathematics
2 answers:
allochka39001 [22]3 years ago
8 0
GCF of 63 and 96 = 3
julia-pushkina [17]3 years ago
4 0
The greatest common factor (GCF) of 63 and 96 is: 3

To find the GCF, list all the factors until that go up to 63 since that is the minimum.
Factors of 63: 1, 3, 7, 9, 21, 63
Factors of 96: 1, 2, 3, 4, 6, 8, 12, 16, 24, 32, 48

Find the common factors between the two numbers which are 1 and 3. Now, which one of those numbers are the greatest/highest? The answer is 3.
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When I think of a number, double it, then add seven, I get 25. what number did I think of?
sweet [91]

Answer:

9

Step-by-step explanation:

25-7=18

half of 18 is 9

5 0
3 years ago
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Which statement is true about the equations-3x 4y 12 and tx 1?
nydimaria [60]

We need to solve -3x+4y=12 for x

Let's start by adding -4y to both sides

-3x+4y-4y=12-4y

-3x=-4y+12

x = (-4y+12)/-3

x= 4/3 y -4

Now substitute 4/3 y -4 for x in 1/4 x - 1/3 y =1

1/4 x -1/3 y =1

1/4 (4/3 y -4) -1/3 y =1

Use the distributive property

(1/4)(4/3 y) + (1/4)(-4) -1/3 y =1

1/3 y -1 - 1/3 y =1

Now combine like terms

(1/3y -1/3y) + (-1) =1

= -1

-1 = 1

Now add 1 to both sides

0=2

So there are no Solutions

The answer is C


I hope that's help Will :)

7 0
3 years ago
If Susie is 14, what was her age x years ago?<br><br> A.) x - 14<br> B.) 14 - x<br> C.) 14x
Cerrena [4.2K]
Susie's age from x years ago would be the difference of her current age and the numbers of years that passed which is x. The expression that best represent her age x years ago is 14 - x. Thus, the answer is letter "B. 14 - x". 
4 0
3 years ago
How many times longer is the wavelength of a sound wave with a frequency of 20 waves per second than the wavelength of a sound w
sergejj [24]

The sound wave with a <u>frequency of 20</u> waves/sec is 800 longer than the wavelength of a sound wave with a <u>frequency of 16,000</u> waves/sec

<h3>Calculating wavelength </h3>

From the question, we are to determine how many times longer is the first sound wave compared to the second sound water

Using the formula,

v = fλ

∴ λ = v/f

Where v is the velocity

f is the frequency

and λ is the wavelength

For the first wave

f = 20 waves/sec

Then,

λ₁ = v/20

For the second wave

f = 16,000 waves/sec

λ₂ = v/16000

Then,

The factor by which the first sound wave is longer than the second sound wave is

λ₁/ λ₂ = (v/20) ÷( v/16000)

= (v/20) × 16000/v)

= 16000/20

= 800

Hence, the sound wave with a <u>frequency of 20</u> waves/sec is 800 longer than the wavelength of a sound wave with a <u>frequency of 16,000</u> waves/sec

Learn more on Calculating wavelength here: brainly.com/question/16396485

#SPJ1

6 0
2 years ago
2 (t-4) + 1 math I ready
Roman55 [17]

Answer:

2t-7

Step-by-step explanation:

Not sure what you need ;( hope this helps!

6 0
3 years ago
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