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pickupchik [31]
3 years ago
9

Please answer correctly !!!!!!!!! Will Mark brainliest !!!!!!!!!!!!!

Mathematics
1 answer:
il63 [147K]3 years ago
6 0

Answer:

x=-\frac{-20+\sqrt{-20w+3600}}{10},\:x=-\frac{-20-\sqrt{-20w+3600}}{10}

Step-by-step explanation:

w=-5\left(x-8\right)\left(x+4\right)\\\mathrm{Expand\:}-5\left(x-8\right)\left(x+4\right):\quad -5x^2+20x+160\\w=-5x^2+20x+160\\Switch\:sides\\-5x^2+20x+160=w\\\mathrm{Subtract\:}w\mathrm{\:from\:both\:sides}\\-5x^2+20x+160-w=w-w\\Simplify\\-5x^2+20x+160-w=0\\Solve\:with\:the\:quadratic\:formula\\\mathrm{Quadratic\:Equation\:Formula:}\\\mathrm{For\:a\:quadratic\:equation\:of\:the\:form\:}ax^2+bx+c=0\mathrm{\:the\:solutions\:are\:}\\x_{1,\:2}=\frac{-b\pm \sqrt{b^2-4ac}}{2a}

\mathrm{For\:}\quad a=-5,\:b=20,\:c=160-w:\quad x_{1,\:2}=\frac{-20\pm \sqrt{20^2-4\left(-5\right)\left(160-w\right)}}{2\left(-5\right)}\\x=\frac{-20+\sqrt{20^2-4\left(-5\right)\left(160-w\right)}}{2\left(-5\right)}:\quad -\frac{-20+\sqrt{-20w+3600}}{10}\\x=\frac{-20-\sqrt{20^2-4\left(-5\right)\left(160-w\right)}}{2\left(-5\right)}:\quad -\frac{-20-\sqrt{-20w+3600}}{10}\\The\:solutions\:to\:the\:quadratic\:equation\:are\\x=-\frac{-20+\sqrt{-20w+3600}}{10},\:x=-\frac{-20-\sqrt{-20w+3600}}{10}

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love history [14]

Martin will have to mark 0.125 on the

Let the original weight of the scale be 1kg. Hence we can say the original mark for 1kg weight is 1 that is:

1kg = 1 ................ 1

Since we are to calculate where to mark for a 1/8 kg weight, we can write;

1/8 kg = x  ..................2

Divide both expressions

\frac{1}{1/8}= \frac{1}{x}\\\\Cross \ multiply\\8= \frac{1}{x} \\x =  \frac{1}{8}

This means Martin will have to mark 0.125 on the scale.

Learn more here: https://brainly.lat/tarea/13002863

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Step-by-step explanation:

x^2 - 16/25 = 0

^^ this might be easier if you separate x^2 and -16

<em>First Step-</em>

so rewrite the problem as x^2/25  -16/25 = 0

then...

<em>Second Step-</em>

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