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Aleonysh [2.5K]

2 years ago

10

Need help on this is mathhhhhhhhhhhhhhhhhhhhhhhhh

1 answer:

pychu [463]2 years ago

8 0

Answer:

38 cm

Step-by-step explanation:

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Plz with steps .. it's very hard can anyone plz

liubo4ka [24]

Answer:

Step-by-step explanation:

$\displaystyle\ \lim_{n \to a} \dfrac{\sqrt{2x}-\sqrt{3x-a} }{\sqrt{x}-\sqrt{a}} =\frac{0}{0} \\\\we\ can \ use\ Hospital's\ Rule\\\\\\f(x)=\sqrt{2x}-\sqrt{3x-a} \qquad f'(x)=\dfrac{2}{2*\sqrt{2x}} -\dfrac{3}{2*\sqrt{3x-a}} \\\\g(x)=\sqrt{x} -\sqrt{a} \qquad g'(x)=\dfrac{1}{2\sqrt{x}} \\\\\\\displaystyle\ \lim_{n \to a} \dfrac{\sqrt{2x}-\sqrt{3x-a} }{\sqrt{x}-\sqrt{a}} =\lim_{n \to a} \dfrac{\dfrac{2}{2*\sqrt{2x}} -\dfrac{3}{2*\sqrt{3x-a}} }{\dfrac{1}{2\sqrt{x}} }\\\\$

$\displaystyle \lim_{n \to a} \dfrac{2\sqrt{x} }{\sqrt{2x}} -\dfrac{3*\sqrt{x} }{\sqrt{3x-a}} =\lim_{n \to a} \dfrac{2 }{\sqrt{2}} -\dfrac{3*\sqrt{x} }{\sqrt{3x-a}}\\\\\\=\dfrac{2}{\sqrt{2}} -\dfrac{3*\sqrt{a} }{\sqrt{2a}}\\\\\\=\dfrac{2}{\sqrt{2}} -\dfrac{3}{\sqrt{2}}\\\\\\=-\ \dfrac{1}{\sqrt{2}}\\\\$

7 0

2 years ago

What is |3|? (Finding absolute values)

dlinn [17]

Answer:

3

Step-by-step explanation:

Whatever number you put between the | | will always come out as positive because of the absolute rule.

$|3|=3$

3 0

3 years ago

Read 2 more answers

Average speed of driving 330 miles in 5 and a half hours

ehidna [41]

The Average speed would be 60 miles per hour.

- Divide 330 by 5.5 hours

8 0

3 years ago

9. If f(x)=-2x^2+4x-6, <br> then f(2)=

Romashka-Z-Leto [24]

Answer:

f(2) = -6

General Formulas and Concepts:

Order of Operations: BPEMDAS

Substitution and Evaluation

Step-by-step explanation:

<u>Step 1: Define</u>

f(x) = -2x² + 4x - 6

f(2) is x = 2

<u>Step 2: Solve</u>

Substitute: f(2) = -2(2)² + 4(2) - 6
Exponents: f(2) = -2(4) + 4(2) - 6
Multiply: f(2) = -8 + 8 - 6
Add: f(2) = -6

3 0

3 years ago

On the first part of a journey, Alan drove a distance of x km and his car used 6 litres of fuel.

irinina [24]

Answer:

$\frac{600}{x+20}\text{ litres per 100 km}$

Step-by-step explanation:

Given,

The number of litres consumed by car in (x+20) km = 6,

So, number of litres consumed by car in 1 km = $\frac{6}{x+20}$ ,

Now, number of litres consumed by car in 100 km = 100 × litres consumed by car in 1 km

$=100\times \frac{6}{x+20}$

$=\frac{600}{x+20}$

Hence, the rate of fuel used by his car would be $\frac{600}{x+20}$ litres per 100 km.

6 0

3 years ago