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agasfer [191]
4 years ago
14

Determine which of the following relations is a function.

Mathematics
2 answers:
grandymaker [24]4 years ago
8 0

Answer: Hi! I am doing the same school program and the answer is A and C! Hope this helps.

fomenos4 years ago
6 0

Answer:

The farthest left box.

Step-by-step explanation:

In order for a relation to be a function, the order of numbers must be constant from the input to the output. The other numbers do not have a consistent value, but the one on the far left is x=+5 and y=-5, and it continues this way throughout the relation.

Hopefully this helped!

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What is the square root of 900
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30

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Denise has a roll of ribbon that is 9 feet
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Your answer would be -12 because of her answers
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Which inequalities correctly show the relationship between the numbers 13, −4, and −17?
lutik1710 [3]

Answer:

13 > -17 < -4

Step-by-step explanation

13 = postive number

-17 and -4 = negtive.

13 is greater than -17

Since negtive is oppistie of postive it goes backwards.

So -4 is greater than -17

(Im new to this so Im not sure if it is correct)

3 0
4 years ago
A quality-conscious disk manufacturer wishes to know the fraction of disks his company makes which are defective. Step 2 of 2 :
stiks02 [169]

Answer:

0.0497 - 1.96\sqrt{\frac{0.0497(1-0.0497)}{322}}=0.026

0.0497 + 1.96\sqrt{\frac{0.0497(1-0.0497)}{322}}=0.073

The 90% confidence interval would be given by (0.026;0.073)

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".  

The margin of error is the range of values below and above the sample statistic in a confidence interval.  

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".  

The population proportion have the following distribution

\hat p \sim N(p,\sqrt{\frac{p(1-p)}{n}})

Solution to the problem

The estimated proportion for this case is:

\hat p =\frac{322-306}{322}= 0.0497

Represent the proportion of defectives for this case

In order to find the critical value we need to take in count that we are finding the interval for a proportion, so on this case we need to use the z distribution. Since our interval is at 90% of confidence, our significance level would be given by \alpha=1-0.90=0.1 and \alpha/2 =0.05. And the critical value would be given by:

z_{\alpha/2}=-1.64, z_{1-\alpha/2}=1.64

The confidence interval for the mean is given by the following formula:  

\hat p \pm z_{\alpha/2}\sqrt{\frac{\hat p (1-\hat p)}{n}}

If we replace the values obtained we got:

0.0497 - 1.96\sqrt{\frac{0.0497(1-0.0497)}{322}}=0.026

0.0497 + 1.96\sqrt{\frac{0.0497(1-0.0497)}{322}}=0.073

The 90% confidence interval would be given by (0.026;0.073)

3 0
3 years ago
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