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drek231 [11]
4 years ago
9

What are the values of x in the equation x2 - 6x + 9 = 25?

Mathematics
2 answers:
tester [92]4 years ago
4 0

Answer:

a

Step-by-step explanation:

hjlf4 years ago
3 0

Answer:

x= -2 or x= 8

Step-by-step explanation:

x^{2} - 6x + 9 = 25

First step, move 25 to the left side so we can do the Quadratic Formula (or you can factor instead.)

x^{2} -6x + 9 - 25 = 0

Next, we know that 9-25 equals -16.

x^{2} - 6x - 16 = 0

Now find that what two numbers multiply and get 16: 2×8 4×4 and 16×1.

Now we do some kind of factoring. The most valuable number must be negative since -6x is negative.

Let's explain about factoring in Quadratic a little bit.

Substitue x²-6x-16 as ax²+bx+c=0

From (ax+d)(bx+c), if we multiply ax and bx, we get the ax²

If we multiply ax and c, we get acx and we multiply d and bx, we get dbx. (axc+bdx) = bx

If we multiply d and c, we get c.

From the factor lf 16, 2×8 seems to be right since -8+2 equals -6 which matches the equation.

Then we get.

(x - 8)(x  + 2) = 0

Seperate both equations.

x - 8 = 0 \\ x + 2 = 0

Find the value of both x.

x = 8 \\ x =  - 2

The answer is x = -2, 8

(The explanation might be weird since I don't know what they are called in English.)

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<img src="https://tex.z-dn.net/?f=14r%20-%208r%3D%20126" id="TexFormula1" title="14r - 8r= 126" alt="14r - 8r= 126" align="absmi
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14r – 8r=126

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R=21

//////////////


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