Answer:
250
Step-by-step explanation:
the solid is made up of 2 regular octagons, 8 sides, joined up by 8 rectangles, one on each side towards the other octagonal face.
from the figure, we can see that the apothem is 5 for the octagons, and since each side is 3 cm long, the perimeter of one octagon is 3*8 = 24.
the standing up sides are simply rectangles of 8x3.
if we can just get the area of all those ten figures, and sum them up, that'd be the area of the solid.
![\bf \textit{area of a regular polygon}\\\\ A=\cfrac{1}{2}ap~~ \begin{cases} a=apothem\\ p=perimeter\\[-0.5em] \hrulefill\\ a=5\\ p=24 \end{cases}\implies A=\cfrac{1}{2}(5)(24)\implies \stackrel{\textit{just for one octagon}}{A=60} \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ \stackrel{\textit{two octagon's area}}{2(60)}~~+~~\stackrel{\textit{eight rectangle's area}}{8(3\cdot 8)}\implies 120+192\implies 312](https://tex.z-dn.net/?f=%5Cbf%20%5Ctextit%7Barea%20of%20a%20regular%20polygon%7D%5C%5C%5C%5C%20A%3D%5Ccfrac%7B1%7D%7B2%7Dap~~%20%5Cbegin%7Bcases%7D%20a%3Dapothem%5C%5C%20p%3Dperimeter%5C%5C%5B-0.5em%5D%20%5Chrulefill%5C%5C%20a%3D5%5C%5C%20p%3D24%20%5Cend%7Bcases%7D%5Cimplies%20A%3D%5Ccfrac%7B1%7D%7B2%7D%285%29%2824%29%5Cimplies%20%5Cstackrel%7B%5Ctextit%7Bjust%20for%20one%20octagon%7D%7D%7BA%3D60%7D%20%5C%5C%5C%5C%5B-0.35em%5D%20%5Crule%7B34em%7D%7B0.25pt%7D%5C%5C%5C%5C%20%5Cstackrel%7B%5Ctextit%7Btwo%20octagon%27s%20area%7D%7D%7B2%2860%29%7D~~%2B~~%5Cstackrel%7B%5Ctextit%7Beight%20rectangle%27s%20area%7D%7D%7B8%283%5Ccdot%208%29%7D%5Cimplies%20120%2B192%5Cimplies%20312)
We are asked to find the equivalent of the expression given:
(3m⁻² n)⁻³
-----------
6mn⁻²
Perform distribution of power using power rule such as shown below:
3⁻³ m⁻²*⁻³n⁻³
-----------------
6mn⁻²
Perform product and quotient rule such as shown below:
m⁶ n²
--------
3³ *6*m*n³
Simplify,
m⁵
--------
162n
The answer is m⁵/162n.
Answer:
Aziza’s claim is incomplete. The third side must be between 4 in. and 26 in.
Step-by-step explanation:
With the Triangle Inequality Theorem, saying that the sum of lengths of any two sides of a triangle is greater than the length of the third side. With this we can develop two inequalities:
11 + 15 > x
26 > x
rewrite this as x < 26
11 + x > 15
x > 15 - 11 Subtract 11 from both sides
x > 4
Therefore, the third side can be anywhere greater than 4 inches and less than and less than 26 inches.
4 < x < 26
Answer:
-4 1/4 , -3 , 3.3, 3 1/3, 4 1/4
Step-by-step explanation:
make all fractions decimals
4 1/4 = 4.25
3 1/3 = 3.33333..
-4 1/4 = -4.25
4.25 , -3 , 3.3 , 3.33... , 4.25
