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3 years ago

Can anybody help solve this?

Mathematics

2 answers:

Inessa [10]3 years ago

3 0

Answer:

ok so. wheres the question

tiny-mole [99]3 years ago

3 0

Answer:

100π and $\frac{500\pi }{3}$

Step-by-step explanation:

<em>The other picture wouldn’t attach, but the radius is 5.</em>

Surface area = 4πr²

r= 5

4.π5²= 25.4.π = 100π

<em>Volume =</em> $\frac{4}{3} \pi r^{3}$

r=5

$\frac{4}{3} \pi 5^{3} = 125.4.\pi$ = $\frac{500\pi }{3}$

Hope this helps ^-^

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Step-by-step explanation:

For this case we know the following propoertis for the random variable X

$\mu = 88, \sigma = 8$

We select a sample size of n = 64

Part a

Since the sample size is large enough we can use the central limit distribution and the distribution for the sample mean on this case would be:

$\bar X \sim N (\mu, \frac{\sigma}{\sqrt{n}})$

With:

$\mu_{\bar X}= 88$

$\sigma_{\bar X}= 8$

Part b

We want this probability:

$P(\bar X>89.7)$

We can use the z score formula given by:

$z = \frac{\bar X -\mu}{\frac{\sigma}{\sqrt{n}}}$

And if we find the z score for 89.7 we got:

$z=\frac{89.7-88}{\frac{8}{\sqrt{64}}}= 1.7$

$P(Z>1.7) = 1-P(Z$

Part c

$P(\bar X$

We can use the z score formula given by:

$z = \frac{\bar X -\mu}{\frac{\sigma}{\sqrt{n}}}$

And if we find the z score for 85.7 we got:

$z =\frac{85.7-88}{\frac{8}{\sqrt{64}}}= -2.3$

$P(Z$

Part d

We want this probability:

$P(87.35$

We find the z scores:

$z =\frac{87.35-88}{\frac{8}{\sqrt{64}}}= -0.65$

$z =\frac{90.5-88}{\frac{8}{\sqrt{64}}}= 2.5$

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