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4 years ago

Can you answer these questions as fast as you can??

Mathematics

1 answer:

Wewaii [24]4 years ago

6 0

70

The information given is that for every 2 students studying physics 3 were studying chemistry

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How can we simplify radicals involving negative values?

RSB [31]

Answer:

using imaginary numbers

Step-by-step explanation:

4 0

3 years ago

Find the number of positive integers less than 100,000 whose digits are among 1, 2, 3, and 4. Hint consider the

Verdich [7]

Answer:

1364 is the number of possibilities for positive integers less than 1,00,000.

Step-by-step explanation:

1. 5 digit numbers:

We have 5 places here, and each place can have 4 options because repetition is allowed.

So, total number of possibilities for 5 digit numbers:

$4 \times 4 \times 4 \times 4 \times 4\\ \Rightarrow 1024$

2. 4 digit numbers:

We have 4 places here, and each place can have 4 options because repetition is allowed.

So, total number of possibilities for 4 digit numbers:

$4 \times 4 \times 4 \times 4 \\ \Rightarrow 256$

3. 3 digit numbers:

We have 3 places here, and each place can have 4 options because repetition is allowed.

So, total number of possibilities for 3 digit numbers:

$4 \times 4 \times 4 \\ \Rightarrow 64$

4. 2 digit numbers:

We have 2 places here, and each place can have 4 options because repetition is allowed.

So, total number of possibilities for 2 digit numbers:

$4 \times 4 \\ \Rightarrow 16$

5. 1 digit numbers:

We have 1 place here, and each place can have 4 options because repetition is allowed.

So, total number of possibilities for 1 digit numbers:

$4$

We can add all the above possibilities to find the total.

So, number of positive integers less than 100,000 whose digits are among 1, 2, 3, and 4 = 1024 + 256 + 64 + 16 + 4 = 1364

3 0

3 years ago

Simplify and solve for x 20 + x = 4x - 4

Monica [59]

Answer:

X= 8

Step by Step Explanation: Hope this helps ya darling!!

6 0

3 years ago

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AURORKA [14]

Answer:

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Step-by-step explanation:

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8 0

4 years ago

the class mean was 72 with a standard deviation of 4.2. Calculate the z-score (to 2 decimal places) for a person who received sc

IrinaVladis [17]

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4 0

3 years ago