Part A. What is the slope of a line that is perpendicular to a line whose equation is −2y=3x+7?
Rewrite the equation −2y=3x+7 in the form
Here the slope of the given line is
If
is the slope of perpendicular line, then

Answer 1: 
Part B. The slope of the line y=−2x+3 is -2. Since
then lines from part A are not parallel to line a.
Since
both lines are not perpendicular to line a.
Answer 2: Neither parallel nor perpendicular to line a
Part C. The line parallel to the line 2x+5y=10 has the equation 2x+5y=b. This line passes through the point (5,-4), then
2·5+5·(-4)=b,
10-20=b,
b=-10.
Answer 3: 2x+5y=-10.
Part D. The slope of the line
is
Then the slope of perpendicular line is -4 and the equation of the perpendicular line is y=-4x+b. This line passes through the point (2,7), then
7=-4·2+b,
b=7+8,
b=15.
Answer 4: y=-4x+15.
Part E. Consider vectors
These vectors are collinear, then
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Answer 5: 
Remark
One of the things you need to do is learn to read phrase by phrase.
What is the quotient of a number and 7? That meas you have a number, x, and it is divided by 7. What you do that the answer you get is the quotient.
x/7 is what you know so for. Now the first part says you take 12 away from that.
x/7 - 12 is what you have after doing that.
The result you get is - 2
x/7 - 12 = - 2 Add 12 to both sides
x/7 - 12 + 12 = - 2 + 12
x/7 = 10 Now multiply by 7
x = 10 *7
x = 70 <<< Answer the number is 70
Answer:
y = 2x - 9
Step-by-step explanation:
y= mx + b
plug in slope
y = 2x + b
plug in points
1 = 2 (5) + b
simplify
1 = 10 + b
subtract 10 each side
-9 = b
plug in to original equation
y=2x - 9