The pool has a diameter 20 ft so: r = 10 ft.
The pool cover extents 12 inches beyond the edge of the pool.
12 inches = 1 foot
Therefore, the radius of the pool cover is : r = 10 + 1 = 11 ft.
a. The area of the pool cover:
A = r² π = 11² π = 121 π ft²
b. The length of the rope:
l = 2 r π = 2 · 11 π = 22 π ft.
S = n(a1 + an)/2
2S = n(a1 + an)
2S = na1 + nan
nan = 2S - na1
an = (2S - n a1)/n
-4/4 can be reduced to -2.
(-8/4) can be reduced to -1.
What you have to do next is to add -1-(-2).
The final answer is 1.
Hope that helps!!!.
Remove these 7 guys from your number
so people who took buses are 318
now divide 318/6 to know how many phone did each bus have
Two triangles are similar if and only if all corresponding angles are equal (congruence), even if the corresponding sides are equal or not, therefore the answer is true because ΔJKL and ΔRST are similar and the statement above demands that "it must be", namely, this is a sufficient condition.
