There are two 5's because the 5 section takes up the amount of 2 sections.
There is a total of 8 sections because sections 2 and 5 take up the amount of 2 sections
5's to total = 2/8 = 1/4
Your answer is A. 1/4
Hope this helps :)
Answer:
<h3>A reflection across the line x=3, a reflection across the x-axis and a dilation with a scale factor of 2, because each side is double.</h3><h3>
Step-by-step explanation:</h3>
We know that the first transfomration is a rotation 90° clockwise.
Notice that vertex R is at the same horizontal coordinate than vertex C, which means the second transformation must include a reflection across the line x=3, a reflection across the x-axis and a dilation with a scale factor of 2, because each side is double.
Step-by-step explanation:
There are four possible values of X: 0 rats show side effects, 1 rat shows side effects, 2 rats show side effects, or all 3 rats show side effects.
Probability X = 0:
P = (1 − 0.5) (1 − 0.4) (1 − 0.3)
P = 0.21
Probability X = 1:
P = (0.5) (1 − 0.4) (1 − 0.3) + (1 − 0.5) (0.4) (1 − 0.3) + (1 − 0.5) (1 − 0.4) (0.3)
P = 0.44
Probability X = 2:
P = (0.5) (0.4) (1 − 0.3) + (0.5) (1 − 0.4) (0.3) + (1 − 0.5) (0.4) (0.3)
P = 0.29
Probability X = 3:
P = (0.5) (0.4) (0.3)
P = 0.06
Answer:
This number "four" is the maximum possible number of positive zeroes (that is, all the positive x-intercepts) for the polynomial f (x) = x 5 – x 4 + 3x 3 + 9x 2 – x + 5. Affiliate However, some of the roots may be generated by the Quadratic Formula , and these pairs of roots may be complex and thus not graphable as x -intercepts.
can calculate and graph the roots (x-intercepts), signs, Local Maxima and Minima, Increasing and Decreasing Intervals, Points of Inflection and Concave Up/Down intervals.
Step-by-step explanation:
Answer:
cement by 5 Kg
Step-by-step explanation:
add the parts of the ratio, 5 + 4 + 1 = 10 parts
Divide the quantity of concrete by 10 to find the value of one part of the ratio.
110Kg ÷ 10 = 11Kg ← value of 1 part of ratio , thus
5 parts = 5 × 11Kg = 55Kg ← cement required
4 parts = 4 × 11Kg = 44Kg ← sand required
1 part = 11Kg ← gravel required
He requires 55Kg of concrete but only has 50Kg.
He requires 44Kg of sand and has 55Kg
He requires 11Kg of gravel and has 15Kg
Thus he is 5Kg short of cement.
