Answer:
She owe $37736.96 after 9 years .
Step-by-step explanation:
Debra borrowed $8000 at a rate of 18% compounded semiannually
We are supposed to find how much will she owe after 9 years
Principal = 8000
Rate of interest = 18% =0.18
No. of compounds per year = 2
Time = 9 years
Formula : 
Substitute the values in the formula :
A= 37736.96
Hence She owe $37736.96 after 9 years .
Answer:
add all the sides together
a+b+c+d
Answer:
800 bacteria
Step-by-step explanation:
Answer of this question depend upon number of hours at the end of day
Let Take Full Day of 24 hrs
Colby bacteria will doubled 12 times ( doubled once in 2hrs => 24/2 = 12)
Colby bacteria at end of day = 50 * 2¹²
Jaquan bacteria will doubled 8 times ( doubled once in 3hrs => 24/3 = 8)
Let say Jaquan bacteria at start of Day = J
Jaquan bacteria at end of day = J * 2⁸
Equating Both
J * 2⁸ = 50 * 2¹²
=> J = 50 * 2⁴
=> J = 50 * 16
=> J = 800
Jaquan will start with 800 Bacteria
Answer:
uhhhh
Step-by-step explanation:
uhhhh
Answer:
n = - 4
Step-by-step explanation:
note that 625 = 
, then
= 
= 
Since the bases on both sides are equal, both 5 then equate the exponents
n = - 4
