The answer to your question is y=-5
Answer:
This a circle centered at the point 
, and of radius "3" as it is shown in the attached image.
Step-by-step explanation:
Recall that the standard formula for a circle of radius "R", and centered at the point 
is given by:
Therefore, in our case, by looking at the standard equation they give us, we extract the following info:
1) 
since the radius must be a positive number and (
) is not a viable answer.
2) 
for ( 
) to equal 
3) 
for ( 
) to equal 
Therefore, we are in the presence of a circle centered at the point , and of radius "3". That is what we draw as seen in the attached image.
a) Is the twitch - initial positive twitch or sudden movement, which is what
makes the car jolt into action.
b) is the acceleration - graph shows the acceleration and
deceleration of the car.
c) is the velocity - starts at 0 and increases until the car
travels at its right speed.
d) is the position - assuming that the car is going on only
one direction. This graph is the only one that does not go back to the x-axis.
Hello!
First of all you look at how many X's the line moves by, in this case it is -3
Then you look at how many y's the line moves by, in this case it is -2
Then you add together the number of X's moved and the number of y's moved:
-3x + -2y
( adding a negative number is the same as subtracting that number)
thus the answer is A. -3x-2y
Hope This helps! :)
Answer:
Correct answer: x₁ = 1 / √3 = √3 / 3 or x₂ = - 1 / √3 = - √3 / 3
Step-by-step explanation:
Given:
3 x⁴ + 14 x² - 5 = 0 biquadratic equation
this equation is solved by a shift x² = t and get:
3 t² + 14 t - 5 = 0
t₁₂ = (-14 ± √14² - 4 · 3 · 5) / 2 · 3 = (-14 ± √196 + 60) / 6
t₁₂ = (-14 ± √256) / 6 = (-14 ± 16) / 6
t₁ = -5 or t₂ = 1 / 3
the solution t₁ = -5 is not accepted because it cannot be x² = -5
we accepted t₂ = 1 / 3
x² = 1 / 3 ⇒
x₁ = 1 / √3 = √3 / 3 or x₂ = - 1 / √3 = - √3 / 3
God is with you!!!
