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3 years ago

SMART PEOPLE PLEASE HELP ME !!!!!!!!!!!!!!!!

Mathematics

2 answers:

Anika [276]3 years ago

6 0

Answer:

B and D

Step-by-step explanation:

rjkz [21]3 years ago

6 0

B and d because / this means divide and b shows that and so does d also 45/100 is basically 0.45

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A cone has a 4 radius and a 8 height what is the volume

Marta_Voda [28]

Hey there! I'm happy to help!

To find the volume of a cone, you multiply the base by the height and then divide by three.

First, we need to find the base. A cone has a circle for the base. To find the area of a circle, we square the radius and multiply it by pi (we will use 3.14).

4²=16

16×3.14= 50.24

Now, we multiply our base by the height.

50.24×8=401.92

Finally, we divide by three.

401.92÷3≈133.973 (to nearest thousandth)

Therefore, the volume of the cone is about 133.973 units cubed. If you were to use exact pi, it would be more like 134 because of all those decimals after pi!

Now you can find the volume of cones!

I hope that this helps! Have a wonderful day!

8 0

3 years ago

The volume V of an ice cream cone is given by V = 2 3 πR3 + 1 3 πR2h where R is the common radius of the spherical cap and the c

Nuetrik [128]

Answer:

The change in volume is estimated to be 17.20 $\rm{in^3}$

Step-by-step explanation:

The linearization or linear approximation of a function $f(x)$ is given by:

$f(x_0+dx) \approx f(x_0) + df(x)|_{x_0}$ where $df$ is the total differential of the function evaluated in the given point.

For the given function, the linearization is:

$V(R_0+dR, h_0+dh) = V(R_0, h_0) + \frac{\partial V(R_0, h_0)}{\partial R}dR + \frac{\partial V(R_0, h_0)}{\partial h}dh$

Taking $R_0=1.5$ inches and $h=3$ inches and evaluating the partial derivatives we obtain:

$V(R_0+dR, h_0+dh) = V(R_0, h_0) + \frac{\partial V(R_0, h_0)}{\partial R}dR + \frac{\partial V(R_0, h_0)}{\partial h}dh\\V(R, h) = V(R_0, h_0) + (\frac{2 h \pi r}{3} + 2 \pi r^2)dR + (\frac{\pi r^2}{3} )dh$

substituting the values and taking $dx=0.1$ and $dh=0.3$ inches we have:

$V(R_0+dR, h_0+dh) =V(R_0, h_0) + (\frac{2 h \pi r}{3} + 2 \pi r^2)dR + (\frac{\pi r^2}{3} )dh\\V(1.5+0.1, 3+0.3) =V(1.5, 3) + (\frac{2 \cdot 3 \pi \cdot 1.5}{3} + 2 \pi 1.5^2)\cdot 0.1 + (\frac{\pi 1.5^2}{3} )\cdot 0.3\\V(1.5+0.1, 3+0.3) = 17.2002\\\boxed{V(1.5+0.1, 3+0.3) \approx 17.20}$

Therefore the change in volume is estimated to be 17.20 $\rm{in^3}$

4 0

3 years ago

Can someone please help

Rufina [12.5K]

Answer: Its A EZ

Step-by-step explanation:

3 0

3 years ago

You have a handful of dimes and quarters that totals 26 coins and is worth $5.15. How many of each do you have?

borishaifa [10]

Answer:

9 dimes and 17 quarters

Step-by-step explanation:

9+17=26 coins

9 dimes = 90 cents

17 = 425 cents

90+425= 515 cents or $5.15

Hope this helps! :)

5 0

3 years ago

Fill the chart for me

yulyashka [42]

6, 1.5, 10, 16, 80, and 2

4 0

3 years ago