Answer:
D
Step-by-step explanation:
Just substitute your point (1,0) to each equation given.
I'll first substitute it into D
y=3(x-1)
0=3(1-1)
0=3(0)
0=0
The answer is D
<span> by taking integral we get
integral sec(x) (tan(x)+sec(x)) dx
applying integral we get
sec(x) (tan(x)+sec(x)) gives sec^2(x)+tan(x) sec(x)
= integral (sec^2(x)+tan(x) sec(x)) dx
Integrate the sum term by term
= integral sec^2(x) dx+ integral tan(x) sec(x) dx
For the integrand tan(x) sec(x), now we will use substitution
substitute u = sec(x) and du = tan(x) sec(x) dx
= integral 1 du+ integral sec^2(x) dx
The integral of sec^2(x) is tan(x)
= integral 1 du+tan(x)
The integral of 1 is u
= u+tan(x)+constant
Substitute the value of u which is equal to
= sec(x):
so our conclusion is
:tan(x)+sec(x)+constant
hope this helps</span>
Answer:
You are using <u>Commutative Property </u>
Step-by-step explanation:
You need to isolate y. When you do, will get y=(4/3)x-2. When the equation is in this form, you can see that the slope is 4/3
