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Alex17521 [72]
3 years ago
14

What's the next step needed to simplify 6(12)-6(5) using the distributive property

Mathematics
1 answer:
Andrej [43]3 years ago
3 0
Distribution is multiplying. So
6(12)-6(5)
72-30
42
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Solve the formula V=pir^2h for r <br><br> PLEAASSSEEE HELP
otez555 [7]

Answer:

B

Step-by-step explanation:

So we have the formula:

V=\pi r^2h

And we want to solve it for r.

So, let's first divide both sides by π and h. This will cancel out the right side:

r^2=\frac{V}{\pi h}

Now, take the square root of both sides:

r=\sqrt{\frac{V}{\pi h}}

And we're done!

Our answer is B.

I hope this helps!

7 0
3 years ago
Read 2 more answers
US
goldfiish [28.3K]

Answer: there are three of the holidays

Step-by-step explanation:

The prime numbers through 31 include 2,3,5,7,11,13,17,19,23,29,31,and 37 so therefore three of the holidays (Martin Luther, Easter, and Thanksgiving) fall on days that are prime numbers

7 0
3 years ago
1) Sally sprints 300 yards in a minute. Quadra runs 20% further than Sally in the same time.
Free_Kalibri [48]
1) answer = 360
explanation =
-> 10% of 300 = 300*10
-> 10% of 300 = 30
-> 20% = 10% x 2
-> 20% = 30 x 2
-> 20% = 60
-> 300 yards ( distance they ran ) + 60 yards ( how much more distance Quadra ran ) = 360 yards
2) answer = Newton spends 10 minutes or 1/6 hours reading
explanation =
-> 25% = 1/4
-> 40*4= 10
-> 1 hrs = 60 min
-> 10 min x 6 = 60 min
-> 1/6 hrs = 10 min
3) answer = 30 fish
explanation =
-> 40% = 12
-> 10% = 3
-> 40*4=10 and 12*4=3
-> 10% + 40% = 50% so 12 + 3 = 15
-> 50% = 15 and 100% = 15 x 2
-> 100% = 30
4) answer = 30
explanation =
-> 1/4 is equal to 25 %
-> add up all the prrcentages ( 25% + 10% + 15% = 50% )
-> she have 50% of tej chocolates Which were in the tin she bought away and kept 15 chocolates to herself
-> 50% = 1/2
-> 50% x 2 = 100%
-> 15 x 2 = 30
3 0
2 years ago
294% as a mixed number in simplest form
Natali5045456 [20]

Answer:

Step-by-step explanation:

294% = 2.94 = 2 and .94 = 2  94/100 = 2 47/50

5 0
2 years ago
Mr. Paulsen challenges Olivia and Angelica to move figure ABCDE onto figure A"B"C"D"E" using a series of two different transform
Jobisdone [24]

Problem 1

One method Olivia could have used is to reflect over the x axis and then translate 10 units to the right.

Let's apply these set of steps to point C.

C = (-2,-4)

C' = (-2,4) after reflecting over the x axis; y coordinate flips in sign

C'' = (8,4) after shifting to the right 10 units; add 10 to the x coordinate

Point C(-2,-4) moves to C''(8,4) which is shown in the diagram. I'll let you check the other four points.

-----------

Another method Olivia could have used is to shift to the right 10 units first, then reflect over the x axis. In this case, the order doesn't matter. Though for some other combinations of transformations, order does matter.

============================================================

Problem 2

Reflecting over the y axis will have the point (x,y) turn into (-x,y). Only the x coordinate changes, and we flip the sign here. The y coordinate stays the same.

A point like C(-2,-4) becomes C'(2,-4) after the y axis reflection. Shifting up 8 units means we add 8 to the y coordinate to arrive at C''(2,4) but this does not match what the diagram shows. Therefore, Angelica's method is incorrect.

You should find other inconsistencies for the other four points as well.

============================================================

Problem 3

Michael's method isn't correct either. He does not apply an x axis reflection and instead relies entirely on translations to move ABCDE to A''B''C''D''E''

At a quick glance, it looks like Michael may be correct. But upon a much closer look, you'll see that things don't line up perfectly.

Instead of point C, we'll pick on point D this time.

D is located at (-6,-2). If we shift up 8 units, then we add 8 to the y coordinate to get to D'(-6,6). Then add 10 to the x coordinate to shift 10 units to the right. This leads us to D''(4,6).

However, the diagram shows D'' is actually at (4,2)

I'll let you check the other points. You should find that only points C and E go to the correct locations, but the other points do not. Again, this is because Michael did not apply an x axis reflection. His figure of A''B''C''D''E'' is upside down compared to what it should be.

============================================================

To summarize, the methods described in problem 1 are the correct way to get ABCDE to move to A''B''C''D''E''. If Olivia followed either of those two methods, then she is correct. Both Angelica and Michael have incorrect methods.

5 0
2 years ago
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