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3 years ago

What is the x-coordinate of the vertex of the parabola whose equation is y = 3x^2 + 12x + 5?

Mathematics

2 answers:

aleksley [76]3 years ago

6 0

(-2, -7) The answer would be -2. I hope that this helped! ;)

ahrayia [7]3 years ago

4 0

Well it will be a simple as grid algebra
3(2+12)+12x5

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statuscvo [17]

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3 years ago

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How do you do this question?

r-ruslan [8.4K]

Step-by-step explanation:

y = 3 + 8x^(³/₂), 0 ≤ x ≤ 1

dy/dx = 12√x

Arc length is:

s = ∫ ds

s = ∫₀¹ √(1 + (dy/dx)²) dx

s = ∫₀¹ √(1 + (12√x)²) dx

s = ∫₀¹ √(1 + 144x) dx

If u = 1 + 144x, then du = 144 dx.

s = 1/144 ∫ √u du

s = 1/144 (⅔ u^(³/₂))

s = 1/216 u^(³/₂)

Substitute back:

s = 1/216 (1 + 144x)^(³/₂)

Evaluate between x=0 and x=1.

s = [1/216 (1 + 144)^(³/₂)] − [1/216 (1 + 0)^(³/₂)]

s = 1/216 (145)^(³/₂) − 1/216

s = (145√145 − 1) / 216

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3 years ago

If a rectangle has a perimeter of 58 ft and a length of 4 feet what is the width of the rectangle?

faltersainse [42]

Answer:

25ft

Hoped this helped!

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2 years ago