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2 years ago

What is the x-coordinate of the vertex of the parabola whose equation is y = 3x^2 + 12x + 5?

Mathematics

2 answers:

aleksley [76]2 years ago

6 0

(-2, -7) The answer would be -2. I hope that this helped! ;)

ahrayia [7]2 years ago

4 0

Well it will be a simple as grid algebra
3(2+12)+12x5

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Which of the equations below could be the equation of this parabola?

Mademuasel [1]

Answer:

Option B: $y = -\frac{1}{2} x^2$

Step-by-step explanation:

The parabola has its concavity downwards, so we need a function in the model:

$y = ax^2 + bx + c$

With a negative value of 'a'

The vertex is (0,0), so we have that:

$0 = 0a + 0b + c$

$c = 0$

The x-coordinate of the vertex is given by the equation:

$x\_vertex = -b/2a$

$-b/2a = 0$

$b = 0$

So we have a function in the model:

$y = ax^2$

With a < 0

The only option with this format is B:

$y = -\frac{1}{2} x^2$

7 0

2 years ago

Billie solved the equation below by completing the square, but she got the incorrect solution. In which step did Billie first ma

Tanzania [10]

Answer:

step 2

Step-by-step explanation:

we have

$x^{2} +10x-49=0$ ---> given problem

step 1

Move the constant to the right side

$x^{2} +10x=49$

the step 1 is correct

step 2

Complete the square

$x^{2} +10x+5^2=49+5^2$

$x^{2} +10x+5^2=74$

<u><em>The step 2 is not correct</em></u>

step 3

Rewrite as perfect squares

$(x+5)^{2}=74$

step 4

take square root both sides

$x+5=\pm\sqrt{74}$

step 5

Find the values of x

$x=-5\pm\sqrt{74}$

$x=-5+\sqrt{74}$

$x=-5-\sqrt{74}$

5 0

3 years ago

1 p

dlinn [17]

Answer:

V = pi * R^2 * h

R = (V / (pi * h))^1/2 = (141.3 / (3.14 * 5))^1/2 = 3 cm

8 0

3 years ago

How do you find x and y?

alexandr1967 [171]

Y=180-111=69
x=360-123-70-69=98
That's your answer.

7 0

3 years ago

HELP PLEASE I will give brainlist

steposvetlana [31]

Answer:

the second one

Step-by-step explanation:

y = 2/3 (x +6)-5

4 0

3 years ago

Read 2 more answers