G divided by 38 = 4 what is four?
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The linear relationship which exists between the change in weight and number of days of hibernation in a hedgedog can be modeled using the equation y = - 0.03 + 0
- Change in weight per day of hibernation = - 0.03
- Change in weight for 115 days = - 3.45 ounces
A linear model can be created using the data in the table given using a regression calculator or excel ;
The linear model obtained in the form y = m + bx is :
- y = - 0.03x + 0
- y = change in weight
- x = number of days of hibernation
- Intercept = 0
- Slope = -0.03
- The slope value of the function gives the change in weight value per number of days of hibernation ; which is -0.03.
- Using the regression equation, substitute, the vlaue of x = 115
- -0.03(115) + 0 = - 3.45
Therefore, the change in weight after 115 days of hibernation is - 3.45 ounces.
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Answer:
Step-by-step explanation:
<em>(17).</em> g(x) = x³ + 4x
f(x) = 4x + 1
( f × g )( x ) = ( x³ + 4x )( 4x + 1 ) = <em>4 </em><em> + x³ + 16x² + 4x</em>
<em>(19).</em> f(t) = 4t - 4
g(t) = t - 2
( 4f + 3g )( t ) = 4(4t - 4) + 3(t - 2) = 16t - 16 + 3t - 6 = <em>19t - 22</em>
<em>(21).</em> h(t) = t + 3
g(t) = 4t + 1
h(t - 2) + g(t - 2) = ( t - 2 ) + 3 + 4( t - 2 ) + 1 = t + 4t - 2 + 3 - 8 + 1 = <em>5t - 6</em>