Answer:
p(w) - - - - - - p = 0.5w ; for 0 < w ≤ 8
p(w) - - - - - - p = 4 ; for w < 8 and w ≤ 12
Step-by-step explanation:
Price, p of weight of a toughurt serving :
p(w) - - - - - - p = 0.5w ; for 0 < w ≤ 8
p(w) - - - - - - p = 4 ; for w < 8 and w ≤ 12
The amount of Cute Puppy food needed for the year is 1140 cans.
<h3>Determining the total number of cans that the dogs eat in a year</h3>
The first step in determining the total number of cans needed in year is to calculate the sum of dog food consumed in a week.
8.25 + 15.5 = 23.75 cans
The second step is to determine the total cans the dogs consume in a month
23.75 x 4 = 95
The third second step is to determine the total cans the dogs consume in a year:
95 x 12 = 1140 cans
<h3>Cost of cute puppy food needed in a year</h3>
1140 x ($21 /40) = $598.50
To learn more about addition, please check: brainly.com/question/19628082
Answer:
Step-by-step explanation:
The first one
Answer:
1368 dollars.
Step-by-step explanation:
given that Jack s purchasing a stock that pays an annual dividend of $3.42 per share
No of shares Jack purchased = 400
Price per share = 53.18$
Amount invested by Jack in shares = 
dollars
Annual dividend = 3.42 per share
Total dividend = 
Annual income from dividends = 1368 $
i. 171
ii. 162
iii. 297
Solution,
n(U)= 630
n(I)= 333
n(T)= 168
i. Let n(I intersection T ) be X
<h3>ii.
n(only I)= n(I) - n(I intersection T)</h3><h3>
= 333 - 171</h3><h3>
= 162</h3>
<h3>
iii. n ( only T)= n( T) - n( I intersection T)</h3><h3>
= 468 - 171</h3><h3>
= 297</h3>
<h3>
Venn- diagram is shown in the attached picture.</h3>
Hope this helps...
Good luck on your assignment...
