Answer:
99y
Step-by-step explanation:
I think is going to be
A=1
B=43
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Any of the 11 man can be chosen, and combined with any of the 8 women.
Assume we select man1. The selected committee can be:
(m1,w1), (m1,w2), (m1,w3), (m1,w4), (m1,w5), (m1,w6), (m1,w7), (m1,w8),
so there are 8 committees selections with man1 in them.
we could repeat the same procedure for the remaining 10 men, and get 8 committees where each of them is a member.
so there are 11*8=88 ways of choosing 1 man and 1 woman.
Answer: 88
Answer:
–21.87 ÷ 4.79
≈ -20 ÷ 5
≈ -4
Step-by-step explanation:
front end estimation means to round off to the most left digit.
eg 12 ≈ 10