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iragen [17]
3 years ago
9

When cai traveled from new orleans to the ozark mountains in arkansas the elevation changed from 7ft below sea level to 2,314 ft

above sea level. How much did the elevation increase?
Mathematics
1 answer:
Tanya [424]3 years ago
7 0

Answer:

2321 ft.

Step-by-step explanation:

When Cai traveled from New Orleans to the Ozark Mountains in Arkansas the elevation changes from 7 ft below sea level to 2314 ft above sea level.

If we consider the elevation below sea level as negative and the elevation above sea level as positive, then the elevation changes from - 7ft to +2314 ft.

Therefore, the increment of elevation is by [2314 - (- 7)] = 2321 ft. (Answer)

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Tuesday's high temperature was 8*C.the low temperature was -1*C .what was the difference between the high and low temperature
arsen [322]

the difference between both of them is 9*C

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3 years ago
What is the answer on this one.
pav-90 [236]

Answer:

On x it is 9, on y it is 37,49

Step-by-step explanation:

8 0
3 years ago
.. Which of the following are the coordinates of the vertices of the following square with sides of length a?
atroni [7]

Option A: O(0,0), S(0,a), T(a,a), W(a,0)

Option D: O(0,0), S(a,0), T(a,a), W(0,a)

Step-by-step explanation:

Option A: O(0,0), S(0,a), T(a,a), W(a,0)

To find the sides of a square, let us use the distance formula,

d=\sqrt{\left(x_{2}-x_{1}\right)^{2}+\left(y_{2}-y_{1}\right)^{2}}

Now, we shall find the length of the square,

\begin{array}{l}{\text { Length } O S=\sqrt{(0-0)^{2}+(a-0)^{2}}=\sqrt{a^{2}}=a} \\{\text { Length } S T=\sqrt{(a-0)^{2}+(a-a)^{2}}=\sqrt{a^{2}}=a} \\{\text { Length } T W=\sqrt{(a-a)^{2}+(0-a)^{2}}=\sqrt{a^{2}}=a} \\{\text { Length } O W=\sqrt{(a-0)^{2}+(0-0)^{2}}=\sqrt{a^{2}}=a}\end{array}

Thus, the square with vertices O(0,0), S(0,a), T(a,a), W(a,0) has sides of length a.

Option B: O(0,0), S(0,a), T(2a,2a), W(a,0)

Now, we shall find the length of the square,

\begin{aligned}&\text { Length } O S=\sqrt{(0-0)^{2}+(a-0)^{2}}=\sqrt{a^{2}}=a\\&\text {Length } S T=\sqrt{(2 a-0)^{2}+(2 a-a)^{2}}=\sqrt{5 a^{2}}=a \sqrt{5}\\&\text {Length } T W=\sqrt{(a-2 a)^{2}+(0-2 a)^{2}}=\sqrt{2 a^{2}}=a \sqrt{2}\\&\text {Length } O W=\sqrt{(a-0)^{2}+(0-0)^{2}}=\sqrt{a^{2}}=a\end{aligned}

This is not a square because the lengths are not equal.

Option C: O(0,0), S(0,2a), T(2a,2a), W(2a,0)

Now, we shall find the length of the square,

\begin{array}{l}{\text { Length OS }=\sqrt{(0-0)^{2}+(2 a-0)^{2}}=\sqrt{4 a^{2}}=2 a} \\{\text { Length } S T=\sqrt{(2 a-0)^{2}+(2 a-2 a)^{2}}=\sqrt{4 a^{2}}=2 a} \\{\text { Length } T W=\sqrt{(2 a-2 a)^{2}+(0-2 a)^{2}}=\sqrt{4 a^{2}}=2 a} \\{\text { Length } O W=\sqrt{(2 a-0)^{2}+(0-0)^{2}}=\sqrt{4 a^{2}}=2 a}\end{array}

Thus, the square with vertices O(0,0), S(0,2a), T(2a,2a), W(2a,0) has sides of length 2a.

Option D: O(0,0), S(a,0), T(a,a), W(0,a)

Now, we shall find the length of the square,

\begin{aligned}&\text { Length OS }=\sqrt{(a-0)^{2}+(0-0)^{2}}=\sqrt{a^{2}}=a\\&\text { Length } S T=\sqrt{(a-a)^{2}+(a-0)^{2}}=\sqrt{a^{2}}=a\\&\text { Length } T W=\sqrt{(0-a)^{2}+(a-a)^{2}}=\sqrt{a^{2}}=a\\&\text { Length } O W=\sqrt{(0-0)^{2}+(a-0)^{2}}=\sqrt{a^{2}}=a\end{aligned}

Thus, the square with vertices O(0,0), S(a,0), T(a,a), W(0,a) has sides of length a.

Thus, the correct answers are option a and option d.

8 0
3 years ago
Select the FOUR equations that are equivalent to 2(x+3)−2=16.
zimovet [89]

Answer:

A (x+3)−1=8open paren x plus 3 close paren minus 1 is equal to 8

C 2(x+3)=182 times open paren x plus 3 close paren is equal to 18

E 2x=122 x is equal to 12

Step-by-step explanation:

Given:

2(x+3) − 2 = 16

2x + 6 - 2 = 16

2x = 16 - 6 + 2

2x = 12

x = 12/2

x = 6

A. (x+3)−1=8

x + 3 - 1 = 8

x = 8 - 3 + 1

x = 6

B (x+3)−2=8

x + 3 - 2 = 8

x = 8 - 3 + 2

x = 7

C 2(x+3)=18

2x + 6 = 18

2x = 18 - 6

2x = 12

x = 12/2

x = 6

D x+3=9x

3 = 9x - x

3 = 8x

x = 3/8

E 2x=12

x = 12/2

x = 6

F 2x=15

x = 15/2

x = 7 1/2

8 0
3 years ago
Can u find the slope intercept form pls?​
Aleks [24]

Answer:

y=(-3/4)x-2

Step-by-step explanation:

slope intercept is y=mx+b

y--5=-3/4(x-4)

y+5=-(3/4)(x-4)

y+5=-(3/4)x-2

y=(-3/4)x-2

6 0
3 years ago
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