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3 years ago

HELP ASAP PLEASE

Mathematics

2 answers:

lianna [129]3 years ago

8 0

B.Get dat loan
Hey thats pretty good

Kryger [21]3 years ago

7 0

If the personal loan has the same starting balance as the credit card, then the loan would be the most responsible decision because it has a lower interest rate which means she'll owe less than if she were to use a credit card.

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Kate wants to build a fence around her yard. The width of the yard is one-third the length. The perimeter of the yard is 80 feet

liq [111]

P = 2(L + W)
P = 80
W = 1/3L

80 = 2(L + 1/3L)
80 = 2(3/3L + 1/3L)
80 = 2(4/3L)
80 = 8/3L
80 * 3/8 = L
240/8 = L
30 = L .... length (L) is 30 ft

W = 1/3L
W = 1/3(30)
W = 30/3
W = 10 <== width (W) = 10 ft

6 0

3 years ago

Read 2 more answers

The distance, d, in kilometres, travelled by a plane after t hours can be represented by d(t)=-4t³=40t²+500t, where t is greater

Ede4ka [16]

D(t) = -4t^3 + 40t^2 + 500t = 4088
4t^3 - 40t^2 - 500t + 4088 = 0
t = 7

Therefore, the plane has flown 4088 km 7 hours after it took off.

8 0

3 years ago

What is the arc length S what is shown below?

Solnce55 [7]

Answer:

14 cm

Step-by-step explanation:

The applicable formula is ...

s = rθ

s = (7 cm)(2) = 14 cm

3 0

3 years ago

A rhombus has a perimeter of 484 feet. What is the length of each side of the rhombus?

LenKa [72]

Each side of the rhombus is 121 feet

5 0

3 years ago

Soap films and bubbles are colorful because the interference conditions depend on the angle of illumination (which we aren't cov

mylen [45]

Answer:

56.39 nm

Step-by-step explanation:

In order to have constructive interference total optical path difference should be an integral number of wavelengths (crest and crest should be interfered). Therefore the constructive interference condition for soap film can be written as,

$2t=(m+\frac{1}{2} ).\frac{\lambda}{n}$

where λ is the wavelength of light and n is the refractive index of soap film, t is the thickness of the film, and m=0,1,2 ...

Please note that here we include an additional 1/2λ phase shift due to reflection from air-soap interface, because refractive index of latter is higher.

In order to have its longest constructive reflection at the red end (700 nm)

$t_1=(m+\frac{1}{2} ).\frac{\lambda}{2.n}\\ \\ t_1=\frac{1}{2} .\frac{700}{(2)*(1.33)}\\ \\ t_1=131.58\ nm$

Here we take m=0.

Similarly for the constructive reflection at the blue end (400 nm)

$t_2=(m+\frac{1}{2} ).\frac{\lambda}{2.n}\\ \\ t_2=\frac{1}{2} .\frac{400}{(2)*(1.33)}\\ \\ t_2=75.19\ nm$

Hence the thickness difference should be

$t_1-t_2=131.58-75.19=56.39 \ nm$

7 0

3 years ago