Suppose JJ = Jhalil , J = Joman
1 - JJ 860 J620
2 - JJ 870 J 670
3- JJ880 J 720
4- JJ890 J 770
5- JJ900 J 820
6- JJ910 J 870
7- JJ920 J 920 - Catched up
8- JJ 930 J 970
9- JJ940 J 1020
10- JJ 950 J 1070
11- JJ960 J 1120
12- JJ 970 J 1170
so a - week 7
b- Joman
Answer:
Step-by-step explanation:
it is your first choice
-4.4+3.6
1.6x
-0.5x
The square root of (64/225) is the same as √64 / √225 .
That could make the whole thing easier.
Do you know what either of those separate square roots is ?
You're right ! I'm so impressed!
The square root of 64 IS 8, and the square root of 225 surely is 15 .
You really know your stuff !
So now, the expression is √64 / √225 = <em>8 / 15</em> .
Oh, I almost forgot, it has a negative sign before it. OK,so the answer is <em>- 8/15</em> .
Answer: To determine the charge on an object, determine the number of excess protons or excess electrons. Multiply the excess by the charge of an electron or the charge of a proton - 1.6 x 10-19 C.
Step-by-step explanation:
