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kotykmax [81]
3 years ago
5

What expression is equivalent to (sin^2x) - (sin x) -2 / sin x-2 ?

Mathematics
1 answer:
VARVARA [1.3K]3 years ago
4 0
The best way to solve this is to substitute: sin x = t.
So:
( t² - t - 2 ) / ( t - 2 ) =
= ( t² - 2 t + t - 2 ) / ( t - 2 ) =
= ( t ( t - 2 ) + ( t - 2 ) ) / ( t - 2 ) =
= ( t - 2 ) ( t + 1 ) / ( t - 2 ) =
= t + 1 = sin x + 1
Answer: sin x + 1
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Answer:

\frac{10}{11}

Step-by-step explanation:

The formula for the trigonometric function sin is:

sinФ=\frac{opposite}{hypotenuse}

The side opposite to the ∠g is x, which is equal to 10

opposite=x      x=10

the hypotenuse of the triangle is z, which is equal to 11

hypotenuse=z    z=11

so the ratio is:

\frac{10}{11}

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3 years ago
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Answer: <u>A. 35</u>

Step-by-step explanation: The largest prime number less than 50. The largest number less than 50 is 49, but it is not prime, because 49=7·7. The previous number is 48, but it is also composite, because 48=2·2·2·2·3. The previous number is 47, it is prime.

The smallest composite number greater than 10. The smallest number greater than 10 is 11, but it is prime. The next number is 12, it is composite, because 12=2·2·3.

The difference between the largest prime number less than 50 and the smallest composite number greater than 10 is<u> 47-12=35.</u>

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3 years ago
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What is the area of a sector in a circle of radius 8cm,if the angle between the radii is 30°
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Answer:

16.75 square cm

Step-by-step explanation:

Area  \: of  \: sector  =  \frac{ \theta}{360 \degree}  \times \pi {r}^{2}  \\  \\  =  \frac{30 \degree}{360 \degree}  \times 3.14 \times  {8}^{2}  \\  \\  =  \frac{1}{12}  \times 3.14 \times 64 \\  \\  =  \frac{1}{3}  \times 3.14 \times 16 \\  \\  =  \frac{1}{3}  \times 50.24 \\  \\  = 16.7466667 \\  \\Area  \: of  \: sector  = 16.75 \:  {cm}^{2}

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KatRina [158]

Answer:

Vel_jet_r =  (464.645 mph)  North + (35.35 mph) East

||Vel_jet_r|| =  465.993 mph

Step-by-step explanation:

We need to decompose the velocity of the wind into a component that can be added  (or subtracted from the velocity of the jet)

The velocity of the jet

500 mph North

Velocity of the wind

50 mph SouthEast = 50 cos(45) East + 50 sin (45) South

South = - North

Vel_ wind = 50 cos(45) mph  East  -  50 sin (45) mph North

Vel _wind =  35.35 mph  East  -  35.35 mph North

This means that the resulting  velocity of the jet is equal to

Vel_jet_r =  (500 mph - 35.35 mph) North + 35.35 mph East

Vel_jet_r =  (464.645 mph)  North + (35.35 mph) East

An the jet has a magnitude velocity of

||Vel_jet_r|| =  sqrt ((464.645 mph)^2 + (35.35 mph)^2)

||Vel_jet_r|| =  465.993 mph

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