All categories

3 years ago

What expression is equivalent to (sin^2x) - (sin x) -2 / sin x-2 ?

1 answer:

4 0

The best way to solve this is to substitute: sin x = t.
So:
( t² - t - 2 ) / ( t - 2 ) =
= ( t² - 2 t + t - 2 ) / ( t - 2 ) =
= ( t ( t - 2 ) + ( t - 2 ) ) / ( t - 2 ) =
= ( t - 2 ) ( t + 1 ) / ( t - 2 ) =
= t + 1 = sin x + 1
Answer: sin x + 1

You might be interested in

14x=x^2-15<br><br> find the value of x

hram777 [196]

Answer: $x=-1, 15$

Step-by-step explanation:

$x^2 -14x-15=0\\\\(x-15)(x+1)=0\\\\x=-1, 15$

5 0

1 year ago

What is the power dissipated by a 5ohm resistor if the current is 4A?

posledela

Answer:

Answer: First, we use Ohm's law ( V = I × R ), to find the current through the resistor. The voltage across the resistor is V = 9 V. The resistance of the resistor is R = 100 Ω. Then, we can use the power rule ( P = I × V ), to find the power dissipated by the resistor

Step-by-step explanation:

i dont know if its the right answer but here

6 0

2 years ago

if a scatter plot has no association then... A.) it has no ordered psirs B.) its ordered pairs have no predictable pattern C.) i

musickatia [10]

Answer:

If a scatter plot has no association then it's ordered pairs have no predictable pattern.

Step-by-step explanation:

8 0

2 years ago

What is the difference? startfraction 2 x 5 over x squared minus 3 x endfraction minus startfraction 3 x 5 over x cubed minus 9

weeeeeb [17]

The difference of the expression $\frac{2x^5}{x^2 - 3x} - \frac{3x^5}{x^3 - 9x}$ is $\frac{2x^5(x + 3) - 3x^5}{x(x - 3)(x + 3)}$

<h3>How to determine the difference?</h3>

The expression is given as:

$\frac{2x^5}{x^2 - 3x} - \frac{3x^5}{x^3 - 9x}$

Factor the denominators of the expressions:

$\frac{2x^5}{x(x - 3)} - \frac{3x^5}{x(x^2 - 9)}$

Apply the difference of two squares to x² - 9

$\frac{2x^5}{x(x - 3)} - \frac{3x^5}{x(x - 3)(x + 3)}$

Take LCM

$\frac{2x^5(x + 3) - 3x^5}{x(x - 3)(x + 3)}$

Hence, the difference of the expression $\frac{2x^5}{x^2 - 3x} - \frac{3x^5}{x^3 - 9x}$ is $\frac{2x^5(x + 3) - 3x^5}{x(x - 3)(x + 3)}$

Read more about expressions at:

brainly.com/question/723406

#SPJ4

6 0

1 year ago

If f(x)= x-3/x , g(x)=x+3 , and h(x)=2x+1 , what is (g*h*f)(x) ?

alexgriva [62]

Answer:

Option B is correct

Step-by-step explanation:

We need to find g(h(f(x))

We first find h(f(x))

f(x) = x-3/x

Putting value of f(x) in place of x in h(x)

h(x) = 2x+1

h(f(x)) = 2(x-3/x) + 1

= 2(x-3/x) + 1

= 2x -6 /x +1

= 2x-6 +x/x

= 3x-6/x

Now, putting value of h(f(x)) in g(x)

g(x) = x+3

g(h(f(x)))= (3x-6/x) + 3

= 3x-6/x + 3

= 3x-6+3x/x

= 6x-6/x

So, Option B is correct.

6 0

3 years ago