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4 years ago

The dot product of u with itself is 12. What is the magnitude of u?

1 answer:

5 0

Dot product is
a*b = |a|*|b|*cosα.
In our case
u*u =|u|*|u|*cos 0
u*u =|u|*|u|
12=|u|²
|u|=√12=√(4*3)=2√3
Answer: <span>D. 2√3</span>

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kap26 [50]

Given:

Area of a sector = 64 m²

The central angle is $\theta=\dfrac{\pi}{6}$ .

To find:

The radius or the value of r.

Solution:

Area of a sector is:

$A=\dfrac{1}{2}r^2\theta$

Where, r is the radius of the circle and $\theta$ is the central angle of the sector in radian.

Putting $A=64,\theta=\dfrac{\pi}{6}$ , we get

$64=\dfrac{1}{2}r^2\times \dfrac{\pi}{6}$

$64=\dfrac{\pi}{12}r^2$

$64\times \dfrac{12}{\pi}=r^2$

$\dfrac{768}{\pi}=r^2$

Taking square root on both sides, we get

$\sqrt{\dfrac{768}{\pi}}=r$

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Therefore, the value of r is $16\sqrt{\dfrac{3}{\pi}}$ m.

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3 years ago

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r-ruslan [8.4K]

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4 years ago

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rodikova [14]

Answer:

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Step-by-step explanation:

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Hence, 41 minutes 40 seconds.

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3 years ago

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exis [7]

Step-by-step explanation:

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