The question is incomplete. Here is the complete question:
During ski season,the owner of ski shop has determined that the number of customers in a day is greater than or equal to 50 more then the temperature(Fahrenheit)
. Write an inequality for the problem and determine the constraints on the variables.
Answer:

Step-by-step explanation:
Let the number of customers be 'N' and the temperature in Fahrenheit be 'T'.
Given:
Number of customers is related to temperature in Fahrenheit as:
Number of customers is greater than or equal to 50 more than the temperature in Fahrenheit. This means,

Now, since 'N' represents number of customers and number can never be a negative quantity. So, the only constraint for this inequality is that the number of customers must be greater than or equal to 0.
So, 
Step 1:
The variable is the number of weeks needed to equalize Alexa and her sisters savings.
Step 2:
7x + 60 = 5x + 120
Step 3:
7x+60=5x+120
Subtract 60 from both sides.
7x+(60-60)=5x+(120-60)
7x=5x+60
Subtract 5x from both sides
7x-5x=5x+60-5x
2x=60
Divide both sides by 2.
2x/2 = 60/2
x=30
Step 4:
7(30) + 60 = 5(30)+ 120
210+60=150+120
270 = 270
Step 5:
To find the unknown amount of weeks, you need to rewrite the equation isolate x on the left-hand side of the equation. I just subtracting/simplified the equation until I could solve it.
(tbh got stuck on this one)
Answer: p value is 0.1685.
Step-by-step explanation:
Since we have given that
The survey is conducted on a random sample of 240 pet owners.
Out of them, number of owners spoke to their pet on telephone = 79
n = 240
x = 79

Our hypothesis would be

Formula for test statistic would be

p value = 0.1685
Hence, p value is 0.1685.
Im sorry i dont know this
Answer:
<em>Problem with the subtraction is </em><em>950 - 863 = 87.</em>
Step-by-step explanation:
Now let us suppose Tim began at number 863 and finished at number 950. The numbers 7 + 30 + 50, or 87 were added.
He later discovered that 863 + 87= 950.
<em>Therefore the problem with the subtraction is 950 - 863 = 87.</em>