The length and width of the rectangle is 11 in and 8 in respectively.
Step-by-step explanation:
Given,
The width of a rectangle is 3 in less than the length.
The area of each congruent right angle triangle = 44 in²
To find the length and width of the rectangle.
Formula
The area of a triangle with b base and h as height =
bh
Now,
Let, the width = x and the length = x+3.
Here, for the triangle, width will be its base and length will be its height.
According to the problem,
×(x+3)×x = 44
or, 
or,
or,
+(11-8)x-88 = 0
or,
+11x-8x-88 =0
or, x(x+11)-8(x+11) = 0
or, (x+11)(x-8) = 0
So, x = 8 ( x≠-11, the length or width could no be negative)
Hence,
Width = 8 in and length = 8+3 = 11 in
Answer:
2/4
Step-by-step explanation:
Change the 2 1/2 to 2 2/4
now subtract 1/4 from 2 2/4 leaving 2 1/4
Now subtract 1 3/4 from 2 1/4 in which you get 2/4
which is the answer :)
Answer:
The correct answer would be the last one; x < 3.
Step-by-step explanation:
Step 1: Simplify both sides of the inequality.
11x - 3 < 30
Step 2: Add 3 to both sides.
11x - 3 + 3 < 30 + 3
11x < 33
Step 3L Divide both sides by 11.
11x/11 < 33/11
Therefor, the correct answer would be the last one: x < 3
Hope this helps!
Answer: 0.75. It's pretty obvious.