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3 years ago

Please answer correctly !!!!!! Will mark brainliest !!!!!!!!!!!!!

Mathematics

1 answer:

Leni [432]3 years ago

4 0

Answer:

At the time of launch height of the object was 60 meters.

Step-by-step explanation:

An object was launched from a platform and its height was modeled by the function,

h(x) = -5x² + 20x + 60

Where x = time or duration after the launch

At the time of launch, x = 0

So, by putting x = 0 in this equation,

h(0) = -5×(0) + 20×(0) + 60

h(0) = 60

Therefore, at the time of launch height of the object was 60 meters.

You might be interested in

What is the order of the numbers from least to greatest

Mrrafil [7]

Answer:

-3.7, -1.9, -1/2, 1 1/3, 1.6, 2 1/3

Step-by-step explanation:

I believe this is correct, if not feel free to let me know and I will fix it. I'm sorry in advance if this answer is wrong.

4 0

3 years ago

Read 2 more answers

Can somone explain to me how to do this and help me thansk!!!

Gnesinka [82]

=> x² = (2.4)² + (4.8)²

=> x² = 5.76 + 23.04

=> x² = 28.8

=> x = 5.366563146

=> x = 5.4

Ans: 2nd option (5.4)

Hope this helps!

6 0

3 years ago

It appears that people who are mildly obese are less active than leaner people. One study looked at the average number of minute

Molodets [167]

Answer:

10.38% probability that the mean number of minutes of daily activity of the 6 mildly obese people exceeds 410 minutes.

99.55% probability that the mean number of minutes of daily activity of the 6 lean people exceeds 410 minutes

Step-by-step explanation:

The Central Limit Theorem estabilishes that, for a random variable X, with mean $\mu$ and standard deviation $\sigma$ , a large sample size can be approximated to a normal distribution with mean $\mu$ and standard deviation $\frac{\sigma}{\sqrt{n}}$ .

Normal probability distribution

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Mildly obese

Normally distributed with mean 375 minutes and standard deviation 68 minutes. So $\mu = 375, \sigma = 68$

What is the probability (±0.0001) that the mean number of minutes of daily activity of the 6 mildly obese people exceeds 410 minutes?

So $n = 6, s = \frac{68}{\sqrt{6}} = 27.76$

This probability is 1 subtracted by the pvalue of Z when X = 410.

$Z = \frac{X - \mu}{s}$

$Z = \frac{410 - 375}{27.76}$

$Z = 1.26$

$Z = 1.26$ has a pvalue of 0.8962.

So there is a 1-0.8962 = 0.1038 = 10.38% probability that the mean number of minutes of daily activity of the 6 mildly obese people exceeds 410 minutes.

Lean

Normally distributed with mean 522 minutes and standard deviation 106 minutes. So $\mu = 522, \sigma = 106$