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Kay [80]
3 years ago
8

Ok so I need help on this ,asap plz :)

Mathematics
1 answer:
soldier1979 [14.2K]3 years ago
4 0
Okay so to do the sqrt(75) you see if there are hidden squares. Split it to be the sqrt(25) and sqrt(3) then simplify. In the end, you get 5sqrt(3). Hope this helps!
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The correct answer is a because it is a
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To whom are you more likely to give a tip of $2?
Lisa [10]
Valet is the answer...
7 0
3 years ago
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3x - y = 7
Nastasia [14]

Answer:

C) -3x=-3

Step-by-step explanation:

When you subtract the 3x-y=7 from 6x-y=10, you will receive the following equation:

3x-6x-y-(-y)=7-10

-3x-y+y=-3

-3x=-3

As we can see, this equation matches the one in option C, meaning that it's our answer!

6 0
2 years ago
1 point) Are the functions f,g, and h given below linearly independent? f(x)=e3x+cos(5x), g(x)=e3x−cos(5x), h(x)=cos(5x). If the
Fynjy0 [20]

Answer:

Functions are linearly dependent (are not linearly independent.)

Step-by-step explanation:

Remember that two functions f(x), g(x) and h(x) are said linearly independent on an interval I if the <em>only solution</em> to the equation

\alpha f(x)+\beta g(x)+\omega h(x)=0, \ \text{for all } x\in I

is the trivial one: α = 0, β = 0, ω = 0. If they are not linearly independent, they are called linearly dependent.

Now, let f(x), g(x) and h(x) be the functions:

f(x)=e^{3x}+\cos(5x),

g(x)=e^{3x}-\cos(5x),

h(x)=\cos(5x).

Then, letting α = 1, β= -1 and ω = -2, we see that:

\alpha f(x)+\beta g(x)+ \omega h(x)=e^{3x}+\cos(5x)-e^{3x}+\cos(5x)+2\cos(5x)=0.

Hence, the functions f(x), g(x) and h(x) are not linearly independent, or equivalently, are linearly dependent.

8 0
2 years ago
What is the solution to the equation below?
romanna [79]

<u>Answer</u>:

- 3

option c). is correct!

<u>Step-by-step explanation</u>:

Given :

5 ( 6 + x ) = 15

= > 30 + 5 x = 15

= > 5 x = - 30 + 15

= > 5 x = - 15

= > x = - 15 / 3

= > x = - 3

Therefore, final answer is - 3

6 0
2 years ago
Read 2 more answers
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