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hichkok12 [17]
3 years ago
8

On a track and field team, 8% of the members run only long-distance, 32% compete only in field events, and 12% are sprinters onl

y. Find the probability that a randomly chosen team member runs only long-distance or competes only in field events.
​
Mathematics
1 answer:
kondor19780726 [428]3 years ago
7 0

Answer:

0.40

Step-by-step explanation:

Members who run only  long distance = 8%

So, probability that a member will run only long distance = P(A) = 0.08

Members who compete only in field events = 32%

So, probability that a member will compete only in field events = P(B) 0.32

Members who are sprinters = 12%

So, probability that a member is sprinter = P(C) 0.12

We have to calculate the probability that a randomly chosen team member runs only long-distance or competes only in field events. i.e we have to find P(A or B). Since these events cannot occur at the same time, we can write:

P(A or B) = P(A) + P(B)

Using the values, we get:

P(A or B) = 0.08 + 0.32 = 0.40

Thus, the probability that a randomly chosen team member runs only long-distance or competes only in field events is 0.40

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Answer:

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Step-by-step explanation:

Consider the provided information.

We have 2.5 mole of dust particles and the Avogadro's number is 6.022\times 10^{23}

Thus, the number of dust particles is:

2.5\times 6.022\times 10^{23}=15.055\times 10^{23}

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Convert the measurement in meters.

Diameter: 10\mu m\times \frac{10^{-6}m}{\mu m} =10^{-5}m

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Circumference in meters:

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\frac{1.5055\times 10^{19}}{40,076,000} = 3.76\times 10^{11}

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