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bija089 [108]
3 years ago
6

How do you determine whether each triangle with sides of given lengths is a right triangle 28, 95, 197?

Mathematics
1 answer:
Dovator [93]3 years ago
8 0
197 is the base , 28 or 95 can be where ever you want on that triangle 
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A pet store sells goldfish and hermit crabs,
Elis [28]

Answer:

Cost = \$28

Step-by-step explanation:

Given

Represent Goldfish with g and hermit crabs with h.

The first statement, we have:

7g + 3h = 26

The second statement, we have:

4g + 5h = 28

Required

Determine the selling price of 6 goldfish and 4 hermit crabs

The equations are:

7g + 3h = 26 --- (1)

4g + 5h = 28 --- (2)

Make g the subject in (2)

4g + 5h = 28

4g = 28 - 5h

Divide both sides by 4

g = \frac{1}{4}(28 - 5h)

Substitute \frac{1}{4}(28 - 5h) for g in (1)

7g + 3h = 26

7(\frac{1}{4}(28 - 5h)) + 3h = 26

\frac{7}{4}(28 - 5h) + 3h = 26

Multiply through by 4

4 * \frac{7}{4}(28 - 5h) + 4*3h = 26*4

7(28 - 5h) + 4*3h = 26*4

Open bracket

196 - 35h + 12h = 104

196 -23h = 104

Collect Like Terms

-23h = 104-196

-23h = -92

Make h the subject

h = \frac{-92}{-23}

h = \frac{92}{23}

h = 4

Substitute 4 for h in g = \frac{1}{4}(28 - 5h)

g = \frac{1}{4}(28 - 5*4)

g = \frac{1}{4}(28 - 20)

g = \frac{1}{4}(8)

g = 2

This implies that:

1 goldfish = $2

1 hermit crab = $4

The cost of 6 goldfish and 4 hermit crabs is:

Cost = 6g + 4h

Cost = 6*\$2 + 4*\$4

Cost = \$12 + \$16

Cost = \$28

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Step-by-step explanation:

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