Cross multiply and solve
1(y^2-9)=6(y-3)
y^2-9= 6y-18
y^2-6y-9+18=0
y^2-6y+9=0
(y-3)(y-3)=0
(y-3)=0
y=3
When you plug y in however, it makes the denominator 0, making both fractions undefined.
Final answer: No real solution
Answer
-200
Step-by-step explanation:
I got the answer because my teacher gave me the answer.
UGH I think I did this before but I totally forgot how to do it. Give me a minute to do some research and remember because I'm about 79% sure I know how to do this!
Just draw a rectangle, cut it into 3 horizontal lines, and cut it into 4 vertical lines.
