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stiv31 [10]
3 years ago
11

Lee watches TV for 2 hours per day. During that time, the TV consumes 250 watts per hour. Electricity costs (10 cents)/(1 kilowa

tt-hour). How much does Lee's TV cost to operate for a month of 30 days?
Mathematics
1 answer:
vladimir1956 [14]3 years ago
6 0

Answer:

$1.5

Step-by-step explanation:

Lets us first calculate energy consumed by TV in 30 days.

Energy consumed by TV in one hour : 250 watts.

TV operated 2 hours a day

so energy consumer by TV in a day = 250 * 2 watts = 500 watts hour

Energy consumed by TV in 30 day = energy consumer by TV in a day * 30

         = 500*30 watts = 15,000 watt-hour

Convert total energy consumed in kilo watt hour  

we know that one kilowatt hour = 1000 watt-hour

Thus, 15,000 watt-hour = 15,000/1000 kilowatt-hour = 15 kilowatt-hour

________________________________

cost of electricity = 10 cents per   kilowatt-hour

cost of electricity for 15 kilowatt-hour = 15* cost of electricity for one  kilowatt-hour( which is 10 cents)

=>15*10 = 150 cents

As $1 = 100 cents

hence 150 cents = $150/100 = $1.5 .

Thus, it cost $1.5 to to operate for a month of 30 days.

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<em><u>The solution is:</u></em>

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<em><u>Solution:</u></em>

We have to solve the given expression

<em><u>Given expression is:</u></em>

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2\frac{1}{12} - 5\frac{5}{6} = \frac{25}{12} - \frac{35}{6}

Make the denominators same for easier calculations

2\frac{1}{12} - 5\frac{5}{6} = \frac{25}{12} - \frac{35 \times 2}{6 \times 2}\\\\2\frac{1}{12} - 5\frac{5}{6} = \frac{25}{12} - \frac{70}{12}\\\\2\frac{1}{12} - 5\frac{5}{6} = \frac{25-70}{12}\\\\2\frac{1}{12} - 5\frac{5}{6} =\frac{-45}{12}

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<em><u>In decimal form, we get</u></em>

\rightarrow \frac{-15}{4} = -3.75

<em><u>Thus the solution is:</u></em>

2\frac{1}{12} - 5\frac{5}{6} = \frac{-15}{4} \text{ or } -3.75

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