Factor completely.
2 answers:
Answer:
A.) (7t³ + 2k^4)(7t³ - 2k^4)
Step-by-step explanation:
This is what we call a conjugate binomial which is two binomials with similar terms but with one of those terms with different signs, this shows a result of the first term squared minus the second term squared.
The formula for conjugate binomials are:
(a+b)(a-b)=
In this case the multiplication of
(7t³ + )(7t³ -
)= 49
+ 14
- 14
-
After substracting the second and the third term you are left with:
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Answer:
a/(bxy) if b≠0, x≠0, y≠0, x≠y
Step-by-step explanation:
You have correctly simplified the expression. The conditions placed on both the original and simplified forms are that none of the denominator factors may be zero. The denominator factors are b, x, y, and (x-y).
Answer:
3 + 11a³ - 7a² + 18a - 18
Step-by-step explanation:
<u>When multiplying with two brackets, you need to multiply the three terms, (a²), (4a) and (-6) from the first bracket to all the terms in the second brackets, (3a²), (-a) and (3) individually. I have put each multiplied term in a bracket so it is easier.</u>
(a² + 4a - 6) × (3a² - a + 3) =
(a² × <em>3a²</em>) + {a² × <em>(-a)</em>} + (a² × <em>3</em>) + (4a × <em>3a²</em>) + {4a × <em>(-a)</em>} + (4a × <em>3</em>) + {(-6) × <em>a²</em>) + {(-6) × <em>(-a)</em>} + {(-6) × <em>3</em>}
<u>Now we can evaluate the terms in the brackets. </u>
(a² × 3a²) + {a² × (-a)} + (a² × 3) + (4a × 3a²) + {4a × (-a)} + (4a × 3) + {(-6) × a²) + {(-6) × (-a)} + {(-6) × 3} =
3 + (-a³) + 3a² + 12a³ + (-4a²) + 12a + (-6a²) + 6a + (-18)
<u>We can open the brackets now. One plus and one minus makes a minus. </u>
3 + (-a³) + 3a² + 12a³ + (-4a²) + 12a + (-6a²) + 6a + (-18) =
3 -a³ + 3a² + 12a³ -4a² + 12a -6a² + 6a -18
<u>Evaluate like terms.</u>
3 -a³ + 3a² + 12a³ -4a² + 12a -6a² + 6a -18 = 3
+ 11a³ - 7a² + 18a - 18