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Anna11 [10]
3 years ago
12

I have an image of the problem

Mathematics
1 answer:
dybincka [34]3 years ago
8 0

Find the area of the circle:

Area = 3.14 x 12^2 = 3.24x144 = 452.16 cm^2

The sector is 60 degrees.

Multiply the area of the circle by the fraction of the sector:

452.16 x 60/360 = 75.36 cm^2

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Tommy finished 3/5 of the race in 6 hour. how long was the entire race?
lesya692 [45]

Hello there,

Well to find the total time you would have to set up a proportion...

6 / 3/5 = x / 1

Now you crosss multiply and divide...

6 * 1 = 6

6 / 3/5 =30/3 = 10


Answer: 10 hours


Hope I helped!!

-Char

7 0
3 years ago
PLEASE HELP I WILL GIVE BRAINALIST
RideAnS [48]

Answer:

They each paid $40

Step-by-step explanation:

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3 years ago
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Phantasy [73]

Answer:

Step-by-step explanation:

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4 0
3 years ago
–2.5 + (–3.5) Which number line shows the sum? (and i know its not -6)
Leto [7]

Answer:

6

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
A sample of 20 pages was taken from a Yellow Pages directory. On each page, the mean area devoted to display ads was measured in
Snezhnost [94]

The 95 percent confidence interval for the mean is (266.76,426.24).

A confidence interval is how much uncertainty there is with any particular statistic. Confidence intervals are often used with a margin of error. It tells you how confident you can be that the results from a poll or survey reflect what you would expect to find if it were possible to survey the entire population. Confidence intervals are intrinsically connected to confidence levels.

The formula of Confidence Interval =  Mean ±   t\frac{Standard Deviation}{\sqrt{number of observations} }

where t is a constant

Given:

Mean = 346.5

Standard Deviation = 170.378

t-critical value for 95% Confidence interval with degrees of freedom(df)=n-1= 19 is 2.093

∴ Substituting values in formula we get

E = 2.093 X170.378/\sqrt{20} = 2.0931.96 x 38.0976=79.74

95% Confidence interval : (346.5-79.74,346.5+79.74)

95% Confidence interval : (266.76,426.24)

Learn more about confidence intervals here :

brainly.com/question/24131141

#SPJ4

4 0
2 years ago
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