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emmasim [6.3K]
3 years ago
13

I NEED HELP ASAP (A new pizza shop opened up and started out$5,344.46 in the hole. Their first month being open they sold 61 piz

zas ($3.06 profit each) and 89 sodas ($1.42 profit each). Thier bills for the first month were $1,208.01. How much money do they still need to make to break even?
Mathematics
1 answer:
cluponka [151]3 years ago
4 0

Answer:

$894.97 is needed more to break even

Step-by-step explanation:

In this question, we want to know how much money the pizza shop need so that their profits will equal their expenses.

Let’s calculate their profit

This can be calculated from the pizza sales

That would be;

61(3.06) + 89(1.42) = $186.66 + $126.38 = $313.04

Now, given that their bills for the first month is $1,208.01, the amount still needed to break even would be the amount of their bills minus the profit made from selling soda and pizza

That would be 1,208.01 - 313.04 = $894.97

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Anna007 [38]

Answer:

The first blank is Reflection across the line x=-3

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for Edumentum/PLATO

Step-by-step explanation:

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7 0
3 years ago
Read 2 more answers
The radioactive isotope carbon-14 is present in small quantities in all life forms, and it is constantly replenished until the o
Fofino [41]

Answer:

a) k = 0.0001245 /year

b) The Shroud of Turin is 757.52 years old.

Step-by-step explanation:

a) dC/dt = - KC

dC/C = - kdt

Integrating the left hand side from C₀ to C₀/2 and the right hand side from 0 to t(1/2) (where t(1/2) is the radioactive isotope's half life)

In [(C₀/2)/C₀] = - k t(1/2)

In (1/2) = - k t(1/2)

- In 2 = - k t(1/2)

k = (In 2)/t₍₁,₂₎

t(1/2) is given in the question to be 5566 years

k = (In 2)/5566 = 0.0001245 /year

b) dC/C = - kdt

Integrating the left hand side from C₀ to C and the right hand side from 0 to t

In (C/C₀) = - kt

C/C₀ = e⁻ᵏᵗ

C = C₀ e⁻ᵏᵗ

When C = 91% of C₀ = 0.91 C₀, solve for t

0.91 C₀ = C₀ e⁻ᵏᵗ

0.91 = e⁻ᵏᵗ

e⁻ᵏᵗ = 0.91

- kt = In 0.91 = -0.00943

t = - 0.00943/(-0.0001245) = 757.52 years.

6 0
3 years ago
Of the cars in the parking lot, 20% are silver. If 20% of the cars is 48 cars, what is the total number of cars in the parking l
astraxan [27]
To solve this, we are going to set up a simple rule of three: If 20% are 48 cars, 100% how many cars will be:
\frac{20----\ \textgreater \ 48}{100----x}
Now, we can express this as a proportion ans solve for x:
\frac{20}{100} = \frac{48}{x}
x= \frac{(100)(48)}{20}
x=240

We can conclude that there are 240 cars in the parking lot.
3 0
3 years ago
Leo sold candy bars for a fundraiser. He spent $25 on a box of candy bars and sold them for $2 each. His profit (after earning b
kykrilka [37]

As given by the question

There are given that the $2c-$25=$69.

Now,

\begin{gathered} $2c-$25=$69$ \\ $2c-$25+25=$69$+25 \\ 2c=$69$+25 \\ 2c=94 \\ c=\frac{94}{2} \\ c=47\text{ bars} \end{gathered}

Hence, the correct answer is C.

4 0
1 year ago
You have just received an inheritance of $28,000 and would like to invest it into an account. The bank offers two investment pla
DiKsa [7]
\bf \qquad \qquad \textit{Amortized Loan Value}
\\\\
pymt=P\left[ \cfrac{\frac{r}{n}}{1-\left( 1+ \frac{r}{n}\right)^{-nt}} \right]

\bf \qquad \qquad \textit{first investment plan}
\\\\\\

\qquad 
\begin{cases}
P=
\begin{array}{llll}
\textit{original amount deposited}\\
\end{array}\to &
\begin{array}{llll}
28000
\end{array}\\
pymt=\textit{periodic payments}\\
r=rate\to 5.8\%\to \frac{5.8}{100}\to &0.058\\
n=
\begin{array}{llll}
\textit{times it compounds per year}\\
\textit{annually, meaning}
\end{array}\to &1\\

t=years\to &4
\end{cases}\\\\


\bf -----------------------------\\\\
\left. \qquad \qquad \right. \textit{2nd investment plan}
\\\\\\
\begin{cases}
P=
\begin{array}{llll}
\textit{original amount deposited}\\
\end{array}\to &
\begin{array}{llll}
28000
\end{array}\\
pymt=\textit{periodic payments}\\
r=rate\to 7.083\%\to \frac{7.083}{100}\to &0.07083\\
n=
\begin{array}{llll}
\textit{times it compounds per year}\\
\textit{annually, meaning again}
\end{array}\to &1\\

t=years\to &3
\end{cases}

see which one yields a bigger "pymt" figure


4 0
4 years ago
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