Answer:
math.way
Step-by-step explanation:
Answer:
Profit = 75
Step-by-step explanation:
Selling price of 3 oranges = 2
There are 210÷3 = 70 set of oranges
Selling price of 1 set (3 oranges) of orange = 2
Selling price of 70 set of oranges = 70 * 2 = 140
Cost of 210 oranges = 65
Profit = selling price - cost price
= 140 - 65
= 75
Answer: The population would be the data of temperatures of all food served by the restaurant.
Step-by-step explanation:
In a statistical study, the term population refers to the largest group of all individuals related to the study or the objective of the study.
Here, the objective of the study= To check the temperatures of food just before serving.
Population = Data of temperatures of all dishes served by restaurant.
Hence, the population would be the data of temperatures of all dishes served by the restaurant.
Part A. You have the correct first and second derivative.
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Part B. You'll need to be more specific. What I would do is show how the quantity (-2x+1)^4 is always nonnegative. This is because x^4 = (x^2)^2 is always nonnegative. So (-2x+1)^4 >= 0. The coefficient -10a is either positive or negative depending on the value of 'a'. If a > 0, then -10a is negative. Making h ' (x) negative. So in this case, h(x) is monotonically decreasing always. On the flip side, if a < 0, then h ' (x) is monotonically increasing as h ' (x) is positive.
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Part C. What this is saying is basically "if we change 'a' and/or 'b', then the extrema will NOT change". So is that the case? Let's find out
To find the relative extrema, aka local extrema, we plug in h ' (x) = 0
h ' (x) = -10a(-2x+1)^4
0 = -10a(-2x+1)^4
so either
-10a = 0 or (-2x+1)^4 = 0
The first part is all we care about. Solving for 'a' gets us a = 0.
But there's a problem. It's clearly stated that 'a' is nonzero. So in any other case, the value of 'a' doesn't lead to altering the path in terms of finding the extrema. We'll focus on solving (-2x+1)^4 = 0 for x. Also, the parameter b is nowhere to be found in h ' (x) so that's out as well.
I don’t know sorry please somebody else can help you
