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beks73 [17]
3 years ago
11

1.The most common way by which data is input into the computer is through the______________.A.Mouse

Computers and Technology
2 answers:
vampirchik [111]3 years ago
6 0

Answer:

keyboard

Explanation:

xxMikexx [17]3 years ago
3 0

Answer:

b

Explanation:

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Write a function called getRowTotal. This function should accept a two-dimensional int array as its first parameter (the array h
garik1379 [7]

Answer:

The solution is implemented using C++

int getRowTotal(int a[][5], int row) {

  int sum = 0;

  for(int i =0;i<5;i++)

  {

      sum += a[row][i];

  }

  return sum;

}

Explanation:

This defines the getRow function and the parameters are arr (the 2 d array) and row and integer variable

int getRowTotal(int arr[][5], int row) {

This defines and initializes sum to 0

  int sum = 0;

This iterates through the row and adds the row items

<em>   for(int i =0;i<5;i++)    { </em>

<em>       sum += arr[row][i]; </em>

<em>   } </em>

This returns the calculated sum

  return sum;

}

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Write a function template called total. The function will keep a running total of values entered by the user, then return the to
pshichka [43]

Answer:

The template is given in C++

Explanation:

#include <iostream>

using namespace std;

//Template function that returns total of all values entered by user

template <class T>

T total (int n)

{

   int i;

   //Initializing variables

   T sum = 0, value;

   //Prompting user

   cout << "\n Enter " << n << " values: \t ";

   //Iterate till user enters n values

   for(i=1; i<=n; i++)

   {

       //Reading a value

       cin >> value;

       //Accumulating sum

       sum = sum + value;

   }

   //Return sum

   return sum;

}

//Main function

int main()

{

   int n;

   //Reading n value

   cout << "\n Enter number of values to process: ";

   cin >> n;

   //Calling function for integers and printing result

   cout << "\n\n Total : " << total<int>(n);

   cout << "\n\n";

   //Function call for doubles and printing results

   cout << "\n\n Total : " << total<double>(n);

   cout << "\n\n";

   return 0;

}

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