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VMariaS [17]
4 years ago
12

Is L.A. film school a private school?

Computers and Technology
2 answers:
marysya [2.9K]4 years ago
7 0
Not too sure, but i think it is. again, not too sure
Fudgin [204]4 years ago
6 0
Is a private institution
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People who rely on others for financial support, such as children and the elderly, are referred to as 16 O A. recipients O B. be
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Answer: dependents

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3 years ago
______ occurs when the system finds itself spending so much time swapping pages into and out from memory that little time is lef
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Answer:

Option b is the correct answer for the above question.

Explanation:

Thrashing occurs when the virtual memory of the computer is more used. It is because the system does not have more memory. That's why the virtual memory is busy in the paging or other work of the operating system and there is no memory left for the other useful work of the system and then Thrashing occurs.

The question statement states the same which is described above and this is the cause when thrashing occurs. Hence the b option is correct. while other is not because--

  • Option "a" states about spooling but spooling is a concept of copy the data.
  • Option C states about an interrupt but it is a concept to stop the work of CPU when any input is coming from the outside.
  • Option D states about a pooling signal which is an operation of computers.

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4 years ago
_______ ______ is the creation of a computer program by utilizing pictorial elements. Question 36 options: A. Assembly Programmi
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I think it's C. Visual Programming 

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4 years ago
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Which program will have the output shown below?
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Let A and B be two stations attempting to transmit on an Ethernet. Each has a steady queue of frames ready to send; A’s frames w
Mariana [72]

Answer:

Following are the solution to the given question:

Explanation:

Please find the complete and correct question in the attachment file.  

For Point a:

For the second round,

A is selects kA(2)  either 0 or 1, so for each of them, that is \frac{1}{2}.

B selects kB(2)\  from\  (0, 1, 2, 3) for each choice with the probability of \frac{1}{4}.

If kA(2) < kB(2) wins the second rear race.

\to P[A \ wins] = P[kA(2) < kB(2)]

                     = P[kA(2) = 0] \times P[kB(2) > 0] + P[kA(2) = 1] \times P[kB(2) > 1]\\\\= \frac{1}{2} \times \frac{3}{4}  + \frac{1}{2}  \times \frac{2}{4} \\\\=\frac{3}{8}  +\frac{2}{8} \\\\= \frac{3+2}{8}\\\\= \frac{5}{8}

For Point b:

Throughout this example, kA(3) also selects to be either 0 or 1 with such a \frac{1}{2} probability. So, although B chooses kB(3) from (0, 1, 2, 3, 4, 5, 6, 7), the probabilities each are \frac{1}{8}:

\to P[A \  wins] = P[kA(3) < kB(3)]

                     = P[kA(3) = 0] \times P[kB(3) > 0] + P[kA(3) = 1] \times P[kB(3) > 1]\\\\= \frac{1}{2} \times \frac{7}{8} + \frac{1}{2} \times \frac{6}{8}\\\\= \frac{7}{16} + \frac{6}{16}\\\\= \frac{7+6}{16} \\\\= \frac{13}{16}\\\\

For point c:

Assume that B tries again 16 times (typical value), and it destroys. In addition, throughout the exponential background n is obtained at 10 when choosing k between 0 to 2n−1. The probability of A winning all 13 backoff events is: P[A \text{wins remaining races}] = 16\pi i =4P[A \ wins \ i |A \ wins \ i -1 ]

Let the k value kA(i) be A for the backoff race I select. Because A retains the breed

=(kA(i)] \cdot P[kA(i+ 1)< kB(i+ 1)] \geq P[kA(i) + 1

For point d:

Two stations A and B are supposed. They assume that B will try 16 times afterward. Even so, for A, 16 races were likely to also be won at a rate of 0.82 For Just higher expectations of three A, B, and C stations. For Station A, possibility to win all backoffs

3 0
3 years ago
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