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postnew [5]
2 years ago
6

The table shows a company's income and expenses over the last 7 days.

Mathematics
1 answer:
tensa zangetsu [6.8K]2 years ago
4 0

Answer:

dont know

Step-by-step explanation:

sorry fam

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When the fraction below is written as a repeating decimal, which digits are repeating?
kaheart [24]
A, 63. If you put in into the calculator, you divide 7 by 11 and you get an answer with a repeating decimal of 6 and 3.
8 0
3 years ago
What is the product of (–0.9)(–2.4)?<br> –3.3<br> –2.16<br> 2.16<br> 3.3
saul85 [17]
The answer would be 2.16.

This is because the two negatives would cancel each other out when multiplying. This would basically make the question 0.9*2.4.
Now 3.3 is definitely not less than 2.4, so the answer would be 2.16
7 0
3 years ago
Read 2 more answers
5. Sara has a photo that is 5 inches by 7 inches. When she adds a frame
stiv31 [10]

Answer:

  1 inch

Step-by-step explanation:

Factors of 63 are 7 and 9, each of which is 2 more than the dimensions of the photo. Sarah's frame is 1 inch wide.

_____

A 1-inch wide frame adds 2 inches to length and width.

_____

<em>Solution using an equation</em>

If you let w represent the width of the frame, the area of the framed photo is ...

  (5+2w)(7+2w) = 63

  4w^2 +24w -28 = 0 . . . . write in standard form

  w^2 +6w -7 = 0 . . . . . . . . divide by 4

  (w -1)(w +7) = 0 . . . . . . . . factor

The positive solution to this equation is w=1.

The width of the frame is 1 inch.

5 0
3 years ago
A spotlight can be adjusted to effectively light a circular area of up to 6 meters in diameter. To the nearest tenth, what is th
levacccp [35]
You would find the radius by halving the diameter. Then you use the equation
\pi \: r { }^{2}  =
and you get about 28.2 meters.
3 0
3 years ago
what is the smallest of 3 consecutive positive integers if the product of smaller two interfere is 5 less than 5 times the large
Lady_Fox [76]

Answer:

Two options:

5,6, and 7

-1,0,and 1

Step-by-step explanation:

Three consecutive natural numbers can be represented as n, n+1, and n+2.

The product of the smaller two would be n(n+1). The less than 5 times the larger is 5(n+2)-5.

Set them equal and solve by factoring:

n(n+1) = 5(n+2) -5\\n^2+n = 5n+10 -5\\n^2+n = 5n+5\\n^2 -4n-5=0\\(n-5)(n+1)=0

Set each factor equal to 0.

n-5==0 so n=5.

n+1=0 so n=-1.

This means the 3 consecutive numbers would be 5,6, and 7

OR

-1, 0 or 1.

8 0
3 years ago
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