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gtnhenbr [62]
3 years ago
13

Help! To solve this system of equations by elimination, what operatfon could be used to eliminate the x-variable and find the va

lue of y?
6x + 5y = 2
4x + 2y = 8
es )
A)
subtract 2 times the second equation from 3 times the first equation
B)
subtract 3 times the second equation from 2 times the first equation
9
subtract 5 times the second equation from 2 times the first equation
D)
subtract 2 times the second equation from 5 times the first equation
Mathematics
1 answer:
NeTakaya3 years ago
7 0

Answer:

c)

subtract 5 times the second equation from 2 times the first equation

Step-by-step explanation:

subtract 5 times the second equation from 2 times the first equation

This will make the coefficient of the y variable 10

for both equations

10y - 10y = 0

leaving only x

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Which one doesn’t belong and why? (look at the picture)
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55 less than 1/3 of the number is 31
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Read 2 more answers
Give the radian measure of an angle drawn in standard position that corresponds with the ray containing the coordinate point (−1
Sergeu [11.5K]

Answer:

The radian measure of the angle drawn in standard position that corresponds with the ray containing the coordinate point (-12, -3\sqrt{2}) is approximately 1.108\pi radians.

Step-by-step explanation:

With respect to origin, the coordinate point belongs to the third quadrant, which comprises the family of angles from \pi\,rad to \frac{3\pi}{2}\,rad. The angle in standard position can be estimated by using the following equivalence:

\theta = \pi\,rad + \tan^{-1} \left(\frac{3\sqrt{2}}{12} \right)

\theta \approx \pi \,rad + 0.108\pi \,rad

\theta \approx 1.108\pi\,rad

The radian measure of the angle drawn in standard position that corresponds with the ray containing the coordinate point (-12, -3\sqrt{2}) is approximately 1.108\pi radians.

5 0
3 years ago
FIND THE MISSING DIMENSION! NEED ASAP! TINY SQUARE IS A =3025 in ²
Nata [24]

Answer:


Step-by-step explanation:

Rule: never completely trust a diagram that comes with a geometry question. This is a case in point. The "tiny" square is actually much larger than the "larger" square.

If you are trying to find the length of the sides of the squares, the formula is

Area = side^2

3025 = side^2

Take the square root of both sides.

sqrt(3025) = sqrt(side^2)

To find the square root of 3025, do the following

Press √

type in 3025

type in =

You should get 55.

======================

The second square is done the same way

√

90.75

=

And you should get 9.526

4 0
3 years ago
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