$20 minus $15 = $5 difference
$5 divided by $0.20 = 25 checks
*Now the accounts are even, except I haven't done the checks for the second account.*
25 checks times $0.10 = $2.50
$2.50 divided by $0.20 = 12.5 checks (round up in this case to 13)
*Now, you need to do 13 more checks on the second account*
13 checks times $0.10 = $1.30
$1.30 divided by $0.20 = 6.5 checks (round up in this case to 7)
*Now, you need to do 7 more checks on the second account*
7 checks times $0.10 = $0.70
$0.70 divided by $0.20 = 3.5 checks (round up in this case to 4)
*Now, you need to do 7 more checks on the second account*
4 checks times $0.10 = $0.40
$0.40 divided by $0.20 = 2 checks
*Now, you need to do 2 more checks on the second account*
2 checks times $0.10 = $0.20
$0.20 divided by $0.20 = 1 check
*Now, you need to do 1 more checks on the second account*
1 checks times $0.10 = $0.10
$0.10 divided by $0.20 = 0.5 checks (round up in this case to 1)
*Now, you need to do 1 more checks on the second account*
1 checks times $0.10 = $0.10
$0.10 divided by $0.20 = 0.5 checks
25 + 13 + 7 + 4 + 2 + 1 + 1 = 53 checks
Check your work!
Account #1- $15 + (53 times $0.20) = $25.60
Account #2- $20 + (53 times $0.10) = $25.30
Answer
53 checks
Answer:
Amount of interest pay per year = $97.5 (Approx.)
Step-by-step explanation:
Given:
Amount borrow for college expenses = $3,897
Rate of interest = 2.5%
Find:
Amount of interest pay per year
Computation:
Using Simple interest formula;
Simple interest = Amount borrow x Rate of interest x number of year
Amount of interest pay per year = 3,897 x 2.5% x 1
Amount of interest pay per year = 3,897 x 0.025
Amount of interest pay per year = 97.425
Amount of interest pay per year = $97.5 (Approx.)
Answer:
Step-by-step explanation:
Given
Required
Evaluate Blue when z = 9
To do this, we simply substitute 9 for z in
Convert indices to fraction
<em>Hence, the blue section has an area of </em>
<em></em>
Answer:
2+w+p
Step-by-step explanation:
The product of a scalar and a matrix is found by multiplying each element of the matrix by the scalar. Multiply each element by -4.
... [4 -12 -24 12]
