OM=18, so OQ=QM=18/2=9.
Given QU=8
from figure OQU is a right angled triangle , so OU^2=OQ^2 + QU^2
OU^2 = 9*9 + 8*8 = 81+72=153;
OU=sqrt(153) = 12.37 =13(approx);
From given statements of congruent NT and OU will also be congruent or identical. So, NT=OU=13
Answer:
p = 14/4
Step-by-step explanation:
-4p+9=-5
-4p = -14
p = 14/4
To determine the perimeter of the triangle given the vertices, calculate the distances between pair of points. For the first pair (-5,1) and (1,1), the distance is 6. For the next pair, (1,1) and (1, -7), the distance is 8. Lastly, for the pair of points (-5,1) and (1, -7), the distance is 10. Adding all the distance will give the perimeter of the triangle. Thus, the perimeter is 24.