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Ksju [112]
3 years ago
14

Aden has a rectangular garden that is A feet wide and B feet long. If he increases each dimension of the garden by 4 feet, what

is the new perimeter of the garden?
Mathematics
1 answer:
alekssr [168]3 years ago
7 0

The only answer I could think of is P=(A+4)+(B+4).

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Please help me up there
Anettt [7]
The answer is 38,400

The scale is 1:40 so the side that is 4 in becomes 160 and the side that is 6 in becomes 240
Multiply 160 and 240 and that is the area of the room

Hope this helps
6 0
3 years ago
Solve for x? I don't think any angle is a 90 degree angle. I didn't draw it exactly right.
Ulleksa [173]
From cosine law
c^2 = a^2 + b^2 -2abcos(C)
cos(C) = (a^2 + b^2 - c^2)/2ab
this formula will solve your problem
4 0
3 years ago
Please help me !!!! trigonometric ratios !!!
DaniilM [7]

Answer:

Step-by-step explanation:

If the questions  is    "What's x" then the answers is...

Use SOH CAH TOA to recall how the trig functions fit on a triangle

SOH: Sin(Ф)= Opp / Hyp

CAH: Cos(Ф)= Adj / Hyp

TOA: Tan(Ф) = Opp / Adj

use CAH

Cos(x) = 46/60

x = arcCos(46/60)

x = 39.9445 °

5 0
3 years ago
How can you tell the zeros of this function by looking at the graph? What are the zeros of the function?
Harrizon [31]
Zero points are these points, where your graph cross x-axis (vertical). And zeros are x values for these points
7 0
3 years ago
Read 2 more answers
Express the equation in rectangular form<br> a) r = 2sin(2Θ)<br> b) r = 4cos(3Θ)
Dafna11 [192]

Answer:

a.  sqrt(x^2+y^2) * (x^2+y^2) = 4xy

b.  (x^2+y^2)^2 = 4x{ (x^2 - 3 y^2}

Step-by-step explanation:

a) r = 2sin(2Θ)

r* = 2 sin 2 theta

We know  sin 2theta = 2 sin theta cos theta

r = 2 * 2 sin theta cos theta

sin theta = y/r  and cos theta = x/r

r = 4 y/r * x/r

r = 4xy / r^2

Multiply each side by r^2

r^3 = 4xy

r * r^2 = 4xy

We know r = sqrt(x^2+y^2)  and r^2 = (x^2+y^2)

sqrt(x^2+y^2) * (x^2+y^2) = 4xy

b) r = 4cos(3Θ)

we know that cos 3 theta = cos^3(theta) - 3 sin^2(theta) cos(theta)

r = 4 *cos^3(theta) - 3 sin^2(theta) cos(theta)

Factor out a cos theta

r = 4 *cos(theta){ cos^2 (theta) - 3 sin^2(theta) }

We know that  sin theta = y/r  and cos theta = x/r

r = 4 (x/r) { (x/r)^2 - 3 (y/r)^2}

r = 4 *(x/r) { (x^2/r^2 - 3 y^2/r^2}

Multiply by r

r^2 = 4x { (x^2/r^2 - 3 y^2/r^2}

Multiply by r^2

r^2 *r^2 = 4x { (x^2 - 3 y^2}

r^4 = 4x{ (x^2 - 3 y^2}

We know  r^2 = (x^2+y^2)

(x^2+y^2)^2 = 4x{ (x^2 - 3 y^2}

5 0
3 years ago
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