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Tpy6a [65]
3 years ago
6

PLZZZ HELLPPP SOON REWARD BRRIANIESTTT

Mathematics
2 answers:
Arte-miy333 [17]3 years ago
6 0
The second one is the first one I think
Oksi-84 [34.3K]3 years ago
6 0

Answer:

I think your answer would be the first one

Step-by-step explanation:

It kind of tells you

if you increase each side, which is 12, by x, you are adding x to each side.

the way i think they want you to put it into A=l*w

area =256

256=l*w

the sides are 12, but added by x

256=12+x^12+x

also written as

256=(12+x)(12+x)

hope this helps!

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The graph of a function g is shown please find the following g(10)
Rama09 [41]

Check the picture below.

3 0
2 years ago
Solve the proportion<br> 16/50 = x/156.25
yuradex [85]
The answer for this proportion is 50.
156.25 times 16 =2,500
2,500 divided by 50=50
X=50
4 0
3 years ago
Read 2 more answers
people ask me sometimes why can’t you do your homework and I say it’s because I help people with theres and they never help me :
shusha [124]

Answer:

6/6 6= 1

Step-by-step explanation:

may be this Is the ans sorry if l am wrong

5 0
3 years ago
Read 2 more answers
If tan0=-3/4 and 0 is in quadrant IV, cos20= (33/25, -17/25, 32/25, 7/25, 24/25?) and tan20= (24/7, -24/7, 7/25, -7/25, 13/7, -1
Oksana_A [137]

Answer:

  • cos(2θ) = 7/25
  • tan(2θ) = -24/7

Step-by-step explanation:

Sometimes, it is easiest to let a calculator do the work. (See below)

__

The magnitude of the tangent is less than 1, so the reference angle will be less than 45°. Then double the angle will be less than 90°, so will remain in the 4th quadrant, where the cosine is positive and the tangent is negative.

You can also use the identities ...

  cos(2θ) = (1 -tan(θ)²)/(1 +tan(θ)²)

  cos(2θ) = (1 -(-3/4)²)/(1 +(-3/4)²) = ((16-9)/16)/((16+9)/16)

  cos(2θ) = 7/25

__

  tan(2θ) = 2tan(θ)/(1 -tan(θ)²) = 2(-3/4)/((16-9/16) = (-6/4)(16/7)

  tan(2θ) = -24/7

3 0
3 years ago
Anna went from home to school with the speed 3 km/hour. She ran back home with the speed 6 km/hour.Her sister Olga went to schoo
PIT_PIT [208]
Let:
v = Olga's speed
t = the time Anna spent going to school (3 km/hour)
t/2 = the time Anna spent running back home with speed of 6 km/hour
So, t + t/2 = 3t/2 is the total time
In the meantime distance = speed*time and the both made the same distance we can put it as:
3t + 6*(t/2) = (3t/2)*v
6t = (3/2)tv divide both sides by t 
(3/2)v = 6
v = 2*6/3
v = 4 km/hour
Olga's speed was 4 km/hour.
3 0
3 years ago
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