Answer:
You would need 2.5
Step-by-step explanation:
You can use a porportion to solve.
(cross multiply and solve)
Answer:
<em>Henson: 3x + y = 163</em>
<em>Garcia: 2x + 3y = 174</em>
<em>adult ticket price: $45</em>
<em>child ticket price: $28</em>
Step-by-step explanation:
Henson Family:
3 adults + 1 child; total $163
3x + y = 163
Garcia Family:
2 adults + 3 children; total $174
2x + 3y = 174
Now we solve the system of equations.
Solve the first equation (Henson Family) for y.
y = 163 - 3x
Substitute 163 - 3x for y in the second equation (Garcia Family).
2x + 3<em>y</em> = 174
2x + 3(<em>163 - 3x</em>) = 174
2x + 489 - 9x = 174
-7x + 489 = 174
-7x = -315
x = 45
Now substitute 45 for x in the first original equation and solve for y.
3x + y = 163
3(45) + y = 163
135 + y = 163
y = 28
adult ticket price: $45
child ticket price: $28
Answer:
3/28
Step-by-step explanation:
Answer:
135 and 135
Step-by-step explanation:
The computation is shown below:
The number of examiners who passed in only one subject is as follows
= n(E) - n(E ∩M) + n(M) - n(E ∩M)
= (80 - 60 + 70 - 60)%
= 30%
Now the number of students who passed in minimum one subject is
n(E∪M) = n(E) + n(M) - n(E ∩M)
= 80 - + 70 - 60
= 90%
Now the number of students who failed in both subjects is
= 100 - 90%
= 10% of total students
= 45
So total number of students appeared for this 450
So, those who passed only one subject is
= 450 × 30%
= 135
Now the Number of students who failed in mathematics is
= 100% - Passed in Mathematics
= 100% - 70%
= 30% of 450
= 135