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lesya692 [45]
3 years ago
5

Which is the best estimate for the liquid volume for a small carton of milk

Mathematics
2 answers:
Stels [109]3 years ago
8 0

Answer: 2 ml

Step-by-step explanation:

1 litre is equal to 1,000 ml, and therefore the best solution is 2 ml.

stepan [7]3 years ago
6 0

Answer:

250 mm

Step-by-step explanation:

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Select the choice which shows all of the diagonals in this polygon and tells how many there are.
Leona [35]

Answer:

Answer C

Step-by-step explanation:

If the polygon has n sides, then the number of diagonals the polygon has is

(n - 3)*n/2

So for a seven sided figure the number of diagonals would be

(7 - 3)(7)/2 = 4*7/2 = 28/2 = 14

6 0
3 years ago
Read 2 more answers
What bedmass question ends with 210
spayn [35]

Answer:

33-9+40-(30+15) =

33-9+40+25-(30+15) =

3+21 x 6-(24-4) =

3+21 x 6-(24-4) x 2 =

(62 ÷ 2 – 3) x 3 +6 =

(62 ÷ 2 – 3) x 3 +6 x 2=

0.3+0.8+0.2=

30+30×0+1=

Step-by-step explanation:

4 0
2 years ago
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The cost of unleaded gasoline in the Bay Area once followed an unknown distribution with a mean of $4.09 and a standard deviatio
WINSTONCH [101]

Answer:

\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})

\mu_{\bar X} = 4.09

\sigma_{\bar X}= \frac{\sigma}{\sqrt{n}}= \frac{0.08}{\sqrt{16}}= 0.02

So the best answer for this case would be:

\bar X \sim N (4.09,  \frac{0.08}{\sqrt{16}}= 0.02)

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".  

Solution to the problem

Let X the random variable that represent the costs of unleaded gasoline of a population, and for this case we know the distribution for X is given by:

X \sim N(4.09,0.08)  

Where \mu=4.09 and \sigma=0.08

We select a sample size of n =16. Since the distribution for X is normal then we know that the distribution for the sample mean \bar X is given by:

\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})

\mu_{\bar X} = 4.09

\sigma_{\bar X}= \frac{\sigma}{\sqrt{n}}= \frac{0.08}{\sqrt{16}}= 0.02

So the best answer for this case would be:

\bar X \sim N (4.09,  \frac{0.08}{\sqrt{16}}= 0.02)

3 0
3 years ago
What are the missing operations?
Ronch [10]

Answer:

Solution in photo

Step-by-step explanation:

6 0
3 years ago
2. Amanda wants to sell her old car. she will open a classified ad in the
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It’s either 64 or 192 if that helps because it say she buys a three week ad would u times 64 by three I’m sorry I don’t have a final answer
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