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il63 [147K]
3 years ago
7

Select the choice which shows all of the diagonals in this polygon and tells how many there are.

Mathematics
2 answers:
Leona [35]3 years ago
6 0

Answer:

Answer C

Step-by-step explanation:

If the polygon has n sides, then the number of diagonals the polygon has is

(n - 3)*n/2

So for a seven sided figure the number of diagonals would be

(7 - 3)(7)/2 = 4*7/2 = 28/2 = 14

ruslelena [56]3 years ago
3 0
The answer would be c
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Pls, help. Trigonometry. Please answer in short sentences I'm not picking. Please answer a-i.​
padilas [110]

Answer:

a . See attachment

b. because we will find the distance from the bottom of the ladder to the base of the building.

c. sin 60 = opposite side / hypotenuse

d.sin 60 = x / 10

e .  8.66 ft =x

f. see attachment

i. cos 60° = adjacent side / hypotenuse

Step-by-step explanation:

a . See attachment

b. because cos 60° = adjacent side / hypotenuse, the hypotenuse is equal to the length of the ladder (10), and the adjacent side that we will find is the distance from the bottom of the ladder to the base of the building. not the height that the ladder reaches .

c. sin 60 = opposite side / hypotenuse

Because we will find the opposite side which is the height that the ladder reaches.

d.sin 60 = x / 10

e .  

0.866025403 = x/10

10 (0.866025403) =x

8.66 ft =x

f. see attachment

i. cos 60° = adjacent side / hypotenuse

Because we will find the adjacent side which is the distance from the bottom of the ladder to the base of the building.

5 0
3 years ago
Assume that adults have IQ scores that are normally distributed with a mean of 96.296.2 and a standard deviation 20.520.5. Find
Sergeeva-Olga [200]

Answer:

The first quartile of the IQ scores of adults is 82.26.

Step-by-step explanation:

The first quartile is the value that is greater than 25% of the observations and less than 75% of the observation.

The formula to compute the first quartile (Q₁) of a Normal distribution is:

Q_{1}=\mu-0.68\sigma

The mean and standard deviation of the IQ scores of adults are:

\mu=96.2\\\sigma=20.5

Compute the first quartile value as follows:

Q_{1}=\mu-0.68\sigma=96.2-(0.68\times20.5)=82.26

Thus, the first quartile of the IQ scores of adults is 82.26.

5 0
3 years ago
I need a little help please
alexandr402 [8]

Answer:

Answer is B I think? :)

Step-by-step explanation:

7 0
3 years ago
What is 9/27 simplified
Vilka [71]
It's 1/3 which can = 0.3333...
7 0
4 years ago
What is the outlier of 29, 2, 28, 30, 26, 31
Vladimir [108]

Answer:

2

Step-by-step explanation:

Given the data : 29, 2, 28, 30, 26, 31

Outlier ;

Lower :Q1 - (1.5 * IQR)

Upper : Q3 + (1.5 * IQR)

Q1 = Lower quartile ; Q3 = upper quartile ; IQR = Interquartile range

Using calculator :

Q1 = 26

Q3 = 30

IQR = (Q3 - Q1) = 30 - 26 = 4

Lower : 26 - (1.5 * 4) = 20

Upper : 30 + (1.5 * 4) = 36

Hence, the number in the given data which falls outside the range is 2

4 0
3 years ago
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