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beks73 [17]
3 years ago
10

HELLPPPP MEEEEEE please!!!!!

Mathematics
1 answer:
steposvetlana [31]3 years ago
6 0

Answer: Branliest plz

ok so for the numbers from 0-150 is one bar, 150-300 is another bar, 300-450 is another bar, and finally 450-600 is the last bar. You put the numbers that go in each different bar i n their seperate bar.

Step-by-step explanation:

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Can you please solve these equations by elimination? -10x -10y=20 , -7x -7y=14.
mash [69]

Answer:

-10x -10y=20

-10x - 20=10y

-10x - 20/10=y

-10x - 2=y

y=-10x-2

-7x -7y=14

-7x - 14 = 7y

-7x - 14/7=y

-7x - 2=y

y=-7x-2

6 0
3 years ago
What is the equation of y = x3 with the given transformations? horizontal translation right 10 units and vertical translation do
Nookie1986 [14]
A. y = (X - 10)^3 - 12
5 0
3 years ago
Read 2 more answers
A home improvement store buys snow shovels from a supplier for $8.50. The day before a snowstorm the store manager marks up the
balandron [24]

Answer:

The retail price is $15.30

Step-by-step explanation:

To solve this, turn the percentage into a decimal. Do this by dividing it by 100.

       180 ÷ 100 = 1.8

Then, multiply the supplier price by the decimal

      8.5 × 1.8 = $15.30

7 0
3 years ago
Let C(n, k) = the number of k-membered subsets of an n-membered set. Find (a) C(6, k) for k = 0,1,2,...,6 (b) C(7, k) for k = 0,
vladimir1956 [14]

Answer:

(a) C(6,0) = 1, C(6,1) = 6, C(6,2) = 15, C(6,3) = 20, C(6,4) = 15, C(6,5) = 6, C(6,6) = 1.

(b) C(7,0) = 1, C(7,1) = 7, C(7,2) = 21, C(7,3) = 35, C(7,4) = 35, C(7,5) = 21, C(7,6) = 7, C(7,7)=1.

Step-by-step explanation:

In this exercise we only need to recall the formula for C(n,k):

C(n,k) = \frac{n!}{k!(n-k)!}

where the symbol n! is the factorial and means

n! = 1\cdot 2\cdot 3\cdot 4\cdtos (n-1)\cdot n.

By convention 0!=1. The most important property of the factorial is n!=(n-1)!\cdot n, for example 3!=1*2*3=6.

(a) The explanations to the solutions is just the calculations.

  • C(6,0) = \frac{6!}{0!(6-0)!} = \frac{6!}{6!} = 1
  • C(6,1) = \frac{6!}{1!(6-1)!} = \frac{6!}{5!} = \frac{5!\cdot 6}{5!} = 6
  • C(6,2) = \frac{6!}{2!(6-2)!} = \frac{6!}{2\cdot 4!} = \frac{5!\cdot 6}{2\cdot 4!} = \frac{4!\cdot 5\cdot 6}{2\cdot 4!} = \frac{5\cdot 6}{2} = 15
  • C(6,3) = \frac{6!}{3!(6-3)!} = \frac{6!}{3!\cdot 3!} = \frac{5!\cdot 6}{6\cdot 6} = \frac{5!}{6} = \frac{120}{6} = 20
  • C(6,4) = \frac{6!}{4!(6-4)!} = \frac{6!}{4!\cdot 2!} = frac{5!\cdot 6}{2\cdot 4!} = \frac{4!\cdot 5\cdot 6}{2\cdot 4!} = \frac{5\cdot 6}{2} = 15
  • C(6,5) = \frac{6!}{5!(6-5)!} = \frac{6!}{5!} = \frac{5!\cdot 6}{5!} = 6
  • C(6,6) = \frac{6!}{6!(6-6)!} = \frac{6!}{6!} = 1.

(b) The explanations to the solutions is just the calculations.

  • C(7,0) = \frac{7!}{0!(7-0)!} = \frac{7!}{7!} = 1
  • C(7,1) = \frac{7!}{1!(7-1)!} = \frac{7!}{6!} = \frac{6!\cdot 7}{6!} = 7
  • C(7,2) = \frac{7!}{2!(7-2)!} = \frac{7!}{2\cdot 5!} = \frac{6!\cdot 7}{2\cdot 5!} = \frac{5!\cdot 6\cdot 7}{2\cdot 5!} = \frac{6\cdot 7}{2} = 21
  • C(7,3) = \frac{7!}{3!(7-3)!} = \frac{7!}{3!\cdot 4!} = \frac{6!\cdot 7}{6\cdot 4!} = \frac{5!\cdot 6\cdot 7}{6\cdot 4!} = \frac{120\cdot 7}{24} = 35
  • C(7,4) = \frac{7!}{4!(7-4)!} = \frac{6!\cdot 7}{4!\cdot 3!} = frac{5!\cdot 6\cdot 7}{4!\cdot 6} = \frac{120\cdot 7}{24} = 35
  • C(7,5) = \frac{7!}{5!(7-2)!} = \frac{7!}{5!\cdot 2!} = 21
  • C(7,6) = \frac{7!}{6!(7-6)!} = \frac{7!}{6!} = \frac{6!\cdot 7}{6!} = 7
  • C(7,7) = \frac{7!}{7!(7-7)!} = \frac{7!}{7!} = 1

For all the calculations just recall that 4! =24 and 5!=120.

6 0
2 years ago
Consider the following geometric sequence.<br><br> 2, 6, 18, 54,
Kaylis [27]

Answer:

The rule or operation in this sequence is multiplication by 3.

Step-by-step explanation:

2*3=6

6*3=18

18*3=54

and so on...

7 0
2 years ago
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