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PilotLPTM [1.2K]
2 years ago
9

F(19) =

\sqrt{x-3}" alt="\frac{3}{x+2}- \sqrt{x-3}" align="absmiddle" class="latex-formula">
Mathematics
1 answer:
Verizon [17]2 years ago
6 0

Answer:

1/7 - 4

1/7 -28/7

\frac{-27}{7}

Step-by-step explanation:

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Choose what the expressions below best represent within the context of the word problem. The length of a rectangle is 12 inches
nexus9112 [7]
The answer is 4. Since 12+ 12 = 24, I added 4 + 4, which made 42.
So the length of the width of the rectangle is 4.
Hope this helps!
3 0
3 years ago
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sarah uses a recipe to make 2 gallons of her favorite mixed berry juice. two of the containers she plans to use to store the jui
MAVERICK [17]
1 gallon=4 quarts=8 pints
1quart=2pints
2 gallons=4*2=8quarts=16pints

2 containers are 1 quart
8-2=6 quarts left

6quars=xpints
12pint=xpints

12 pint containers
3 0
3 years ago
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What is the simplified expression for 3^3 x 3^3/ 3^4
Juli2301 [7.4K]

Answer:

9

Step-by-step explanation:

\frac{3^{6} }{3^{4} }

3^{2}

9

3 0
4 years ago
Which of the following is true?
Ratling [72]

In this question, we're trying to find the inequality that is true.

To find your answer, we can convert the numbers in the absolute value:

|−5| < 4:

5 < 4 <em>false</em>

|−4| < |−5|:

4 < 5 <em>true </em>

|−5| < |4|

5 < 4 <em>false</em>

|−4| < −5

4 < -5 <em>false</em>

The only true inequality here would be |−4| < |−5|, since it works with the inequality sign.

Answer:

|−4| < |−5|

4 0
3 years ago
Please help me!<br> Find the number x such that f(x) =1
STatiana [176]

Answer:

D

Step-by-step explanation:

We have the piecewise function:

f(x) = \left\{        \begin{array}{ll}            -\frac{1}{2}x-1 & \quad x \leq -2 \\            x & \quad x > -2        \end{array}    \right.

And we want to find x such that f(x)=1.

So, let's substitute 1 for f(x):

1 = \left\{        \begin{array}{ll}            -\frac{1}{2}x-1 & \quad x \leq -2 \\            x & \quad x > -2        \end{array}    \right.

This has two equations. So, we can separate them into two separate cases. Namely:

1=-\frac{1}{2}x-1\text{ or } 1=x

Let's solve for x in each case.

Case I:

We have:

1=-\frac{1}{2}x-1

Add 1 to both sides:

2=-\frac{1}{2}x

Let's cancel out the fraction by multiplying both sides by -2. So:

2(-2)=(-2)\frac{-1}{2}x

The right side cancels:

-4=x\\

Flip:

x=-4

So, x is -4.

Case II:

We have:

1=x

Flip:

x=1

This is the solution for our second case.

So, we have:

x_1=-4\text{ or } x_2=1

Now, can check to see if we have to to remove solution(s) that don't work.

Note that x=-4 is the solution to our first equation.

The first equation is defined only if x is less than -2.

-4 <em>is </em>less than -2. So, x=-4 is indeed a solution.

x=1 is the solution to our second equation.

The second equation is defined only if x is greater than or equal to -2.

1 <em>is</em> greater than or equal to -2. So, x=1 is <em>also </em>a solution.

Therefore, our two solutions are:

x_1=-4\text{ or } x_2=1

Out of our answer choices, we can pick D.

And we're done!

7 0
3 years ago
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